java 配置的会话工厂：null
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Configured SessionFactory: null
提问by Piraba
I have created basic hibernate application. It throw error message.
我已经创建了基本的休眠应用程序。它抛出错误消息。
Error is:
错误是：
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Environment <clinit>
INFO: Hibernate 3.2.5
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Environment <clinit>
INFO: hibernate.properties not found
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: Bytecode provider name : cglib
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Environment <clinit>
INFO: using JDK 1.4 java.sql.Timestamp handling
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Configuration configure
INFO: configuring from resource: /hibernate.cfg.xml
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Configuration getConfigurationInputStream
INFO: Configuration resource: /hibernate.cfg.xml
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Configuration addResource
INFO: Reading mappings from resource : com/crmcall/entity/CallUsers.hbm.xml
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.HbmBinder bindRootPersistentClassCommonValues
INFO: Mapping class: com.crmcall.entity.CallUsers -> crmcallusers
Oct 18, 2012 3:36:13 PM org.hibernate.cfg.Configuration addResource
INFO: Reading mappings from resource : com/crmcall/entity/Customers.hbm.xml
Oct 18, 2012 3:36:14 PM org.hibernate.cfg.HbmBinder bindRootPersistentClassCommonValues
INFO: Mapping class: com.crmcall.entity.Customers -> crmcustomermaster
Oct 18, 2012 3:36:14 PM org.hibernate.cfg.Configuration addResource
INFO: Reading mappings from resource : com/crmcall/entity/User.hbm.xml
Oct 18, 2012 3:36:14 PM org.hibernate.cfg.HbmBinder bindRootPersistentClassCommonValues
INFO: Mapping class: com.crmcall.entity.User -> crmusers
Oct 18, 2012 3:36:14 PM org.hibernate.cfg.Configuration doConfigure
INFO: Configured SessionFactory: null
Initial SessionFactory creation failed.org.hibernate.MappingException: component class not found: string
Exception in thread "main" java.lang.ExceptionInInitializerError
at com.crmcall.util.HibernateUtil.<clinit>(HibernateUtil.java:27)
at com.crmcall.dao.UserDAO.<init>(UserDAO.java:23)
at com.crmcall.dao.UserDAO.main(UserDAO.java:36)
Caused by: org.hibernate.MappingException: component class not found: string
at org.hibernate.mapping.Component.getComponentClass(Component.java:104)
at org.hibernate.tuple.component.PojoComponentTuplizer.buildGetter(PojoComponentTuplizer.java:133)
at org.hibernate.tuple.component.AbstractComponentTuplizer.<init>(AbstractComponentTuplizer.java:43)
at org.hibernate.tuple.component.PojoComponentTuplizer.<init>(PojoComponentTuplizer.java:38)
at org.hibernate.tuple.component.ComponentEntityModeToTuplizerMapping.<init>(ComponentEntityModeToTuplizerMapping.java:52)
at org.hibernate.tuple.component.ComponentMetamodel.<init>(ComponentMetamodel.java:50)
at org.hibernate.mapping.Component.buildType(Component.java:152)
at org.hibernate.mapping.Component.getType(Component.java:145)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:253)
at org.hibernate.mapping.RootClass.validate(RootClass.java:193)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1102)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1287)
at com.crmcall.util.HibernateUtil.<clinit>(HibernateUtil.java:24)
... 2 more
Caused by: java.lang.ClassNotFoundException: string
at java.net.URLClassLoader.run(URLClassLoader.java:200)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276)
at java.lang.ClassLoader.loadClass(ClassLoader.java:251)
at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:319)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:169)
at org.hibernate.util.ReflectHelper.classForName(ReflectHelper.java:100)
at org.hibernate.mapping.Component.getComponentClass(Component.java:101)
This is my Hibernate.cfg.xml file:
这是我的 Hibernate.cfg.xml 文件：
<hibernate-configuration>
<session-factory>
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://192.168.1.5:3306/crmtest</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">root</property>
<property name="hibernate.hbm2ddl.auto">create-drop</property>
<property name="show_sql">true</property>
<property name="format_sql">true</property>
<!-- Enable Hibernate automatic session context management -->
<property name="current_session_context_class">thread</property>
<!-- Disable the second-level cache -->
<property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
<mapping resource="com/crmcall/entity/CallUsers.hbm.xml"/>
<mapping resource="com/crmcall/entity/Customers.hbm.xml"/>
<mapping resource="com/crmcall/entity/User.hbm.xml"/>
</session-factory>
</hibernate-configuration>
This is my User.hbm.xml
这是我的 User.hbm.xml
<hibernate-mapping>
<class name="com.crmcall.entity.User" table="crmusers">
<composite-id name="userPK" >
<key-property name="businessUnit" column="BusinessUnit" type="string"/>
<key-property name="userID" column="UserID" type="string"/>
</composite-id>
<property name="recID" >
<column name="RecID"/>
</property>
<property name="password">
<column name="Password"/>
</property>
<property name="userName">
<column name="UserName"/>
</property>
<property name="userType">
<column name="UserType"/>
</property>
<property name="userLevel">
<column name="UserLevel"/>
</property>
<property name="customerCode">
<column name="CustomerCode"/>
</property>
<property name="customerCodeson">
<column name="CustomerCodeson"/>
</property>
<property name="locationCode">
<column name="LocationCode"/>
</property>
<property name="lastUpdatedBy">
<column name="LastUpdatedBy"/>
</property>
<property name="lastUpdatedOn" type="timestamp">
<column name="LastUpdatedOn"/>
</property>
<property name="email" type="string">
<column name="Email"/>
</property>
</class>
</hibernate-mapping>
This is my calling place :
这是我打电话的地方：
public class UserDAO {
private Session session = null;
public UserDAO() {
session = HibernateUtil.currentSession();
}
public List<User> getAllUsers() {
Transaction tn = session.beginTransaction();
List<User> users = session.createQuery("from crmusers cu order by cu.UserID").list();
System.out.println("==" + users.size());
tn.commit();
return users;
}
public static void main(String[] args){
UserDAO userDAO = new UserDAO();
userDAO.getAllUsers();
}
}
This is my project folder structre:
这是我的项目文件夹结构：
Please tell me what is an issue in my code?
请告诉我我的代码有什么问题？
Thanks in advance..
提前致谢..
回答by Johanna
In User.hbm.xml you have to use type="java.lang.String"(with a big 'S'). That's it.
在 User.hbm.xml 中，您必须使用type="java.lang.String"（带有一个大的“S”）。而已。
回答by dimas
AS I understand the problem in your code was caused by your User.hbm.xmlmapping file. To be more precised by type="string"attribute of composite-idtab.
据我了解，您的代码中的问题是由您的User.hbm.xml映射文件引起的。通过复合 ID选项卡的type="string"属性更精确。
As I understand you don't need to put type attribute obligatory so try to skip it at all; hibernate should detect it automatically. I'm not sure in last sentece because I have not used composite keys, but there are a lot of examples where peoples don't define type explicitly.
据我了解，您不需要强制输入 type 属性，因此请尝试跳过它；休眠应该自动检测它。我不确定最后一句，因为我没有使用复合键，但是有很多例子人们没有明确定义类型。
回答by Anders R. Bystrup
Hmmm, in your mapping file you have
嗯，在你的映射文件中你有
<key-property name="businessUnit" column="BusinessUnit" type="string"/>
<key-property name="userID" column="UserID" type="string"/>
That should be ...type="java.lang.String"...instead, but most likely you really don't need it - Hibernate will make a (usually very good) educated guess.
那应该是...type="java.lang.String"...，但很可能你真的不需要它 - Hibernate 会做出（通常非常好的）有根据的猜测。
Cheers,
干杯，
回答by subodh
Hibernate use the reflectionto determine the mapping type at runtime.
It seems your mapping is correct, But if you still getting the same problem.
I will suggestyou to remove the type attributefor the time being test, from all the Stringtype properties such as email,businessUnit,userId
Hibernate 使用reflection来确定映射类型runtime。看起来你的映射是正确的，但如果你仍然遇到同样的问题。我会建议您type attribute暂时从所有String类型属性（例如电子邮件、业务单位、用户 ID）中删除测试
try this way for all the Stringtype properties
对所有String类型属性尝试这种方式
<property name="email">
<column name="Email"/>
</property>
or you can try with java.lang.Stringalso
或者你可以尝试java.lang.String也
<property name="email" type="java.lang.String">
<column name="Email"/>
</property>
回答by Steve Ebersole
Both "string" and "java.lang.String" are aliases for org.hibernate.type.StringType, so either should work in terms of naming types.
"string" 和 "java.lang.String" 都是 org.hibernate.type.StringType 的别名，所以两者都应该在命名类型方面起作用。
I am actually not so sure the problem is in the mapping for User. That mapping looks fine. Based on that exception I would more expect that somewhere you have
我实际上不太确定问题出在用户的映射中。那个映射看起来不错。基于那个例外，我更希望你在某个地方
<composite-id ... class="string">
or
或者
<component ... class="string">
or something like that.
或类似的东西。
回答by mrArbi
<composite-id name="userPK" >
<key-property name="businessUnit" column="BusinessUnit" type="String"/>
<key-property name="userID" column="UserID" type="String"/>
</composite-id>
try with changing string to String
尝试将字符串更改为字符串
