C语言 使用 pid 启动 gdb
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start gdb using a pid
提问by Vijay
In general i see the process's pidwhich is running in the background and start dbx on that process using the command dbx -a <pid>
一般来说，我会看到pid在后台运行的进程，并使用命令在该进程上启动 dbxdbx -a <pid>
similarly how could i do it using gdb?
同样，我如何使用 gdb 做到这一点？
采纳答案by R Samuel Klatchko
There are two ways.
有两种方法。
From the command line, include the pid as an argument after the executable name:
在命令行中，在可执行文件名称后包含 pid 作为参数：
gdb /path/to/prog PID
From within gdb, you can use the attach command:
在 gdb 中，您可以使用 attach 命令：
gdb /path/to/prog
gdb> attach PID
While the specifying on the command line is more concise, there is a slight risk that if you have a core file that has a name that is the same as the pid (i.e. for pid 2345, the core file would have to be named "2345") then gdb will open the core file. Admittedly, the chance of this happening is minuscule.
虽然在命令行上指定更简洁，但如果您有一个名称与 pid 相同的核心文件（即对于 pid 2345，核心文件必须命名为“2345 ") 然后 gdb 将打开核心文件。诚然，这种情况发生的可能性微乎其微。
回答by zakkak
In addition to the previous you can directly use
除了前面的你可以直接使用
gdb -p <pid>
回答by janm
From the gdb man page:
从 gdb 手册页：
You can, instead, specify a process ID as a second argument, if you want to debug a running process:
如果要调试正在运行的进程，则可以将进程 ID 指定为第二个参数：
gdb program 1234
