Linux 将特定的十六进制模式从 bash 写入文件
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Write a certain hex pattern to a file from bash
提问by Falcata
I am trying to do some memory tests and am trying to write a certain hex pattern to a regular file from bash. How would I go about doing this without using the xxd or hexdump tool/command?
我正在尝试进行一些内存测试,并尝试从 bash 将某个十六进制模式写入常规文件。如果不使用 xxd 或 hexdump 工具/命令,我将如何执行此操作?
Thanks, Neco
谢谢,尼科
回答by William Pursell
The simplest thing is probably:
最简单的事情大概是:
printf '\xde\xad\xbe\xef' > file
but it is often more convenient to do
但这样做往往更方便
perl -e 'print pack "H*", "deadbeef"' > file
回答by Ivaylo Strandjev
If I get your question correctly printf should do:
如果我正确回答了您的问题, printf 应该这样做:
>printf %X 256
100
回答by blueshift
Can you use od -x
instead? That's pretty universaly available, od has been around since the dawn of time[1]
你可以用od -x
吗?这是非常普遍可用的,od 从一开始就存在 [1]
[1] Not really the dawn of time.
[1] 并不是真正的黎明。
回答by GreyCat
Memory testing is muchmore complex subject than just writing / reading patterns in memory. Memory testing puts pretty hard limits on what a testing program can do and what state the whole system is in. Technically, it's impossible to test 100% of memory when you're running regular OS at all.
内存测试比仅仅在内存中写入/读取模式要复杂得多。内存测试对测试程序可以做什么以及整个系统所处的状态进行了非常严格的限制。从技术上讲,当您运行常规操作系统时,根本不可能测试 100% 的内存。
On the other hand, you can run some real test program from a shell, or schedule test execution on next boot with some clever hacking around. You might want to take a look at how it's done in Inquisitor, i.e. running memtester for in-OS testingand scheduling memtest86* run on next boot.
另一方面,您可以从 shell 运行一些真正的测试程序,或者在下次启动时通过一些巧妙的 hacking 安排测试执行。您可能想看看它是如何在 Inquisitor 中完成的,即运行 memtester 进行操作系统内测试并安排 memtest86* run on next boot。
If you absolutely must remain in your current booted OS, then probably memtester would be your tool of choice - although note that it's not very precise memory test.
如果您绝对必须留在当前启动的操作系统中,那么 memtester 可能是您的首选工具 - 尽管请注意,它不是非常精确的内存测试。
回答by Devidas
There are multiple ways to do this in bash one of the way is
\x31
'\' is used to skip next charcter from bash decoding
'x' show its a hex number
在 bash 中有多种方法可以做到这一点,其中一种方法是
\x31 '\' 用于跳过 bash 解码中
的下一个字符'x' 显示其十六进制数
echo -en \x31\x32\x33 > test
-e to avoid trailing line (else 0x0A will apend at end)
-n to interprete backslash escapes
-e 避免尾随行(否则 0x0A 将附加在末尾)
-n 解释反斜杠转义