C语言 将 ASCII 数字转换为 C 中的 ASCII 字符
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Convert ASCII number to ASCII Character in C
提问by Anonymous
In C is there a way to convert an ASCII value typed as an int into the the corresponding ASCII character as a char?
在 C 中有没有办法将输入为 int 的 ASCII 值转换为相应的 ASCII 字符作为字符？
回答by taskinoor
You can assign intto chardirectly.
您可以分配int到char直接。
int a = 65;
char c = a;
printf("%c", c);
In fact this will also work.
事实上，这也将起作用。
printf("%c", a); // assuming a is in valid range
回答by Fred Foo
If iis the int, then
如果i是int，那么
char c = i;
makes it a char. You might want to add a check that the value is <128if it comes from an untrusted source. This is best done with isasciifrom <ctype.h>, if available on your system (see @Steve Jessop's comment to this answer).
使其成为char. 您可能想要添加检查值<128是否来自不受信任的来源。如果在您的系统上可用，最好使用isasciifrom完成<ctype.h>（请参阅@Steve Jessop 对此答案的评论）。
回答by Jonathan Wood
If the number is stored in a string (which it would be if typed by a user), you can use atoi()to convert it to an integer.
如果数字存储在字符串中（如果由用户键入），则可以使用atoi()将其转换为整数。
An integer can be assigned directly to a character. A character is different mostly just because how it is interpreted and used.
整数可以直接分配给字符。一个字符之所以不同，主要是因为它的解释和使用方式。
char c = atoi("61");
