Javascript 语法错误:JSON.parse:意外字符

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时间:2020-08-24 07:00:15  来源:igfitidea点击:

SyntaxError: JSON.parse: unexpected character

phpjavascriptjqueryajaxjson

提问by Art

I'm having a problem. I have a json code as below. I want to parse them but get an error: SyntaxError: JSON.parse: unexpected character I don't know where is the error. Would anyone help?

我有问题。我有一个 json 代码,如下所示。我想解析它们但得到一个错误: SyntaxError: JSON.parse: 意外字符我不知道错误在哪里。有人会帮忙吗?

My js code:

我的js代码:

  function retreive() {
  var userInfo = new Array();
  userInfo[0] = $("#contactId").val();
  userInfo[1] = $("#pw").val();
  var cId = $.ajax({ 
    url: "server.php", 
    type: "POST", 
data: {phpData : userInfo}, 
    datatype: "json",
success:function(msg) {
    responseJson = JSON.parse(msg.responseText);
var outputHtml = "";
    for (var i=0; i<responseJSON.user.mary.length; i++) {
outputHtml += responseJSON.user.mary[i].sender[i].sendDate + 
", " + responseJSON.user.mary[i].sender[i].time + 
", " + responseJSON.user.mary[i].sender[i].timezone + 
", " + responseJSON.user.mary[i].sender[i].message + "<br/>"}
divMessage = document.getElementById("message");
    divMessage.innerHTML = outputHtml;
}
});   

}

}

my php code:

我的 php 代码:

    $data = '{
  "user" : 
    [
      {
    "mary" :
      [
        {
          "sender1" :
        [
              {
                "sendDate"     : "2012-01-13",
                "time"     : "15:00:21",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "hi"
          },
          {
                "sendDate"     : "2012-01-18",
                "time"     : "16:00:01",
                "timezone" : "Asia/Hong_Kong",
            "message"  : "how are you"
              },
              {
                "sendDate"     : "2012-01-21",
                "time"     : "14:31:42",
                "timezone" : "Asia/Hong_Kong",
            "message"  : "good"
          }  
        ],
          "sender2" :
        [
          {
                "sendDate"     : "2012-01-14",
                "time"     : "09:01:25",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "good morning"
          },
              {
                "sendDate"     : "2012-01-14",
                "time"     : "09:03:41",
            "timezone" : "Asia/Hong_Kong",
                "message"  : "where are you"
          },
          {
                "sendDate"     : "2012-01-14",
                "time"     : "09:05:42",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "me too"
          }
            ],
        }  
      ],    
    "peter" :
      [
        {
          "sender1" :
            [         
              {
                "sendDate"     : "2012-01-13",
                "time"     : "10:44:28",
            "timezone" : "Asia/Hong_Kong",
                "message"  : "hey man"
          },
          {
                "sendDate"     : "2012-01-13",
                "time"     : "10:46:11",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "what are you doing"
              },
              {
                "sendDate"     : "2012-01-13",
                "time"     : "10:48:33",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "nice"
          }
        ],
          "sender3" :
            [
              {
                "sendDate"     : "2012-01-18",
                "time"     : "14:23:58",
            "timezone" : "Asia/Hong_Kong",
                "message"  : "Had you send the file to me"
              },
          {
                "sendDate"     : "2012-01-18",
                "time"     : "15:01:39",
            "timezone" : "Asia/Hong_Kong",
                "message"  : "i have not receive yet"
          },
              {
                "sendDate"     : "2012-01-19",
                "time"     : "09:08:32",
                "timezone" : "Asia/Hong_Kong",
                "message"  : "received"
          },
        ],  
        }
      ],
      }
    ],
}';
echo $data;

回答by Utkanos

Well, like the error says, your JSON is invalid.

好吧,就像错误所说的那样,您的 JSON 无效。

http://jsonlint.com/

http://jsonlint.com/

Constructing JSON manually is a really bad idea. It's far harder to construct, and you're prone to parse errors. Instead, build your data programmatically as an array or object then use json_encode().

手动构建 JSON 是一个非常糟糕的主意。构建起来要困难得多,而且您很容易出现解析错误。相反,以编程方式将数据构建为数组或对象,然后使用json_encode().

回答by epoch

JSON Lintis your friend, use it to find potential errors in your json.

JSON Lint是您的朋友,用它来查找 json 中的潜在错误。

Parse error on line 45:
...                   }            ],   
----------------------^
Expecting 'STRING'