laravel 如何验证 Laravel4 中的选择框输入
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/17235444/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to validate select box input in Laravel4
提问by eski009
Currently when I want to validate a select box I need to include all the values within the validation field.
目前，当我想验证一个选择框时，我需要在验证字段中包含所有值。
public static $rules = array(
'type' => array('required', 'in:a,b,c,d')
);
Is there a best practise way to do this using an array?
是否有使用数组执行此操作的最佳实践方法？
For example: I have a long list of country names and want to include this as the validation list. The hacky way of doing this would be something along the lines of:
例如：我有一个很长的国家/地区名称列表，并希望将其作为验证列表包含在内。这样做的hacky方式将是：
public static $rules = array(
'type' => array('required', 'in:'.implode(',', $countries))
);
Thanks
谢谢
采纳答案by Rob Gordijn
A custom is possible, but a exist-rule can also do the job. More details on http://laravel.com/docs/validation#rule-exists
自定义是可能的，但存在规则也可以完成这项工作。有关http://laravel.com/docs/validation#rule-exists 的更多详细信息
回答by Clem
Create a select menu with an array like so:
创建一个带有数组的选择菜单，如下所示：
$types = [ '' => 'select a type',
'one' => 'type one',
'a' => 'type a' ];
And rules for validation like so:
和验证规则如下：
$rules = ['type' => 'required'];
As the first key of $types is an empty string. Will output like this:
因为 $types 的第一个键是一个空字符串。会像这样输出：
<option value=''>select a type</option>
On validation the required rule will fail validation.
在验证时，所需的规则将无法通过验证。
Assuming all options in the select menu are valid options.
假设选择菜单中的所有选项都是有效选项。
