C++ 错误 - 'char' 和 'int' 之前的预期主表达式
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C++ error - expected primary expression before 'char' and 'int'
提问by Naxical
#include<iostream>
#include<cstring>
using namespace std;
class Employee
{
char name[5];
int id;
int age;
public:
Employee(char* a, int b, int c)
{
strcpy(name, a);
id=b;
age=c;
}
};
class Officer: public Employee
{
char officer_cadre[3];
public:
Officer(char* a, int b, int c, char* d):Employee(char* a, int b, int c)
{
strcpy(officer_cadre, d);
}
};
int main()
{
Officer o1("Nakul", 1, 2, "ABC");
return 0;
}
The above code is simple, but I'm not able to figure out why the compiler is throwing errors like 'expected primary expression before char' and 'expected primary expression before int'.
上面的代码很简单，但我无法弄清楚为什么编译器会抛出诸如“char 之前的预期主表达式”和“int 之前的预期主表达式”之类的错误。
回答by RonaldBarzell
Change this line:
更改此行：
Officer(char* a, int b, int c, char* d):Employee(char* a, int b, int c)
To this:
对此：
Officer(char* a, int b, int c, char* d):Employee(a,b,c)
Also I am concerned about your declaration of officer_cadre. It's an array of character pointers, but there's no memory allocation. Was that the declaration you meant?
我也很担心你对offer_cadre 的声明。它是一个字符指针数组，但没有内存分配。那是你说的宣言吗？
回答by Doug T.
On this line
在这条线上
Officer(char* a, int b, int c, char* d):Employee(char* a, int b, int c)
You should just pass a,b, and c. Instead you are using the syntax to declare a,b, and c. When just referring to them you don't need the types. IE you should do:
你应该只通过 a、b 和 c。相反，您使用语法来声明 a、b 和 c。当只是引用它们时，您不需要类型。IE 你应该这样做：
Officer(char* a, int b, int c, char* d):Employee(a, b, c)
You may have just accidentally copy-pasted the declaration into the child class's constructor.
您可能只是不小心将声明复制粘贴到子类的构造函数中。
回答by kord
Change
改变
char* officer_cadre[3];
to
到
char officer_cadre[3];
