bash 每个循环的 shell 脚本中的增量数
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时间：2020-09-18 02:28:46 来源:igfitidea点击:
Incremental number in shell script on each loop
提问by ahmet
#!/bin/bash
echo SCRIPT: so it READs 10000028 uses it on first loop
2nd 10000029
3rd 10000030
4th 10000031
echo "Enter Customer Order Ref (e.g. 100018)"
read P_CUST_ORDER_REF
echo "Enter DU Id (e.g. 100018)"
read P_DU_ID
P_ORDER_ID=${P_CUST_ORDER_REF}${P_DU_ID}
#Loop through all XML files in the current directory
for f in *.xml
do
#Increment P_CUST_ORDER_REF here
done
Inside the for loop how can i increment P_CUST_ORDER_REF by 1 every time it loops
在 for 循环中，如何在每次循环时将 P_CUST_ORDER_REF 增加 1
((P_CUST_ORDER_REF+=1))
回答by Prince John Wesley
let P_CUST_ORDER_REF+=1
or
或者
P_CUST_ORDER_REF=$((P_CUST_ORDER_REF+1))
回答by mouviciel
(( P_CUST_ORDER_REF++ ))
回答by Paused until further notice.
You can use the post-increment operator:
您可以使用后增量运算符：
#!/bin/bash
is_pos_int () {
[[ =~ ^([1-9][0-9]*|0)$ ]]
}
echo "SCRIPT: ##代码##"
read -rp 'Enter Customer Order Ref (e.g. 100018)' p_cust_order_ref
is_pos_int "$p_cust_order_ref"
read -rp 'Enter DU Id (e.g. 100018)' p_du_id
is_pos_int "$p_dui_id"
p_order_id=${p_cust_order_ref}${p_du_id}
#Loop through all XML files in the current directory
for f in *.xml
do
(( p_cust_order_ref++ ))
done
I recommend:
我建议：
- habitually using lowercase or mixed case variable names to avoid potential name collision with shell or environment variables
- quoting all variables when they are expanded
- usually using
-rwith read to prevent backslashes from being interpreted as escapes - validating user input
- 习惯性地使用小写或大小写混合的变量名，以避免与 shell 或环境变量的潜在名称冲突
- 展开时引用所有变量
- 通常使用
-rwith read 来防止反斜杠被解释为转义 - 验证用户输入
For example:
例如：
##代码##