javascript 我可以在 Python 和 Selenium 中使用正则表达式找到一个元素吗？
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Can I find an element using regex with Python and Selenium?
提问by alecxe
I need to click a dropdown list and click a hidden element with in it. the html will be generated by javascript and I won't know the id or class name but I will know it will have a phrase in it. Can I find and element by regex and then click it with selenium?
我需要单击下拉列表并单击其中的隐藏元素。html 将由 javascript 生成，我不知道 id 或类名，但我知道它会有一个短语。我可以通过正则表达式查找和元素，然后用硒单击它吗？
回答by alecxe
You cannot simply do regex-based search with built-in selenium webdriver locators, but you have multiple things that might help you:
您不能简单地使用内置的 selenium webdriver 定位器进行基于正则表达式的搜索，但是您有多种方法可以帮助您：
contains()andstarts-with()XPath functions://div[contains(., "Desired text")] //div[starts-with(., "Desired text")]preceding,preceding-sibling,followingandfollowing-siblingaxis that might help you if you know the relative position of an newly generated block of elements you need to locate
contains()和starts-with()XPath 函数：//div[contains(., "Desired text")] //div[starts-with(., "Desired text")]preceding,preceding-sibling,following和following-siblingaxis 如果您知道需要定位的新生成元素块的相对位置，可能会对您有所帮助
There are also CSS selectorsfor partial match on element attributes:
还有用于元素属性部分匹配的CSS 选择器：
a[href*=desiredSubstring] # contains
a[href^=desiredSubstring] # starts-with
a[href$=desiredSubstring] # ends-with
And you can always find more elements than needed and filter them out later in Python, example:
你总是可以找到比需要更多的元素，然后在 Python 中过滤掉它们，例如：
import re
pattern = re.compile(r"^Some \w+ text.$")
elements = driver.find_elements_by_css_selector("div.some_class")
for element in elements:
match = pattern.match(element.text)
if match:
print(element.text)
回答by MelArlo
You can use import reto perform regex functions. The snippet below looks through a table and grabs the text between the <b></b>tags in the first cell if the row has 3 cells in it.
您可以使用import re来执行正则表达式功能。<b></b>如果该行中有 3 个单元格，下面的代码段会查看一个表格并抓取第一个单元格中标签之间的文本。
import re
from lxml import html, etree
tree = html.fromstring(browser.page_source)
party_table = tree.xpath("//table")
assert len(party_table) == 1
CURRENT_PARTIES = []
for row in party_table[0].xpath("tbody/tr"):
cells = row.xpath("td")
if len(cells) != 3:
continue
if cells[1].text == "represented by":
match = re.search(r'<b>(.+?)</b>', etree.tostring(cells[0]), re.IGNORECASE)
print "MATCH: ", match
