Java 在不使用数组的情况下从整数中获取最低和最高值？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/19435242/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Getting the lowest and highest value from integers without using arrays?
提问by Dinco
I'm trying to write a class which reads 5 integers from the user and returns the highest and lowest value back. This must be done using loops and without using arrays and Integer.MIN.Value/Integer.MAX.Value. I've already succeeded writing code that gets 5 integers from the user and returns the highest value but I just can't get both the highest and the lowest value returned in the same class.
我正在尝试编写一个类，该类从用户读取 5 个整数并返回最高和最低值。这必须使用循环来完成，而不使用数组和 Integer.MIN.Value/Integer.MAX.Value。我已经成功编写了从用户那里获取 5 个整数并返回最高值的代码，但我无法同时获得同一类中返回的最高值和最低值。
Here is the code I mentioned above:
这是我上面提到的代码：
import java.util.Scanner;
public class Ovning_321 {
public static void main(String[] args){
Scanner input = new Scanner(System.in);
int number;
int max = 0;
for (int x = 0; x<5; x++){
System.out.print("Give me an integer: ");
number = input.nextInt();
if (number > max){
max = number;
}
}
System.out.println("Highest value: " + max);
}
}
采纳答案by necromancer
here you go :)
干得好 ：）
import java.util.Scanner;
public class Ovning_321 {
public static void main(String[] args){
Scanner input = new Scanner(System.in);
int number;
int max = 0;
int min = 0;
for (int x = 0; x<5; x++){
System.out.print("Give me an integer: ");
number = input.nextInt();
if (x == 0 || number > max){
max = number;
}
if (x == 0 || number < min){
min = number;
}
}
System.out.println("Highest value: " + max);
System.out.println("Lowest value: " + min);
}
}
回答by underbar
Why not just repeat your max logic for min?
为什么不重复你的最大逻辑最小值？
public class Ovning_321 {
public static void main(String[] args){
Scanner input = new Scanner(System.in);
System.out.print("Give me an integer: ");
number = input.nextInt();
int max = number;
int min = number;
for (int x = 0; x<4; x++){
System.out.print("Give me an integer: ");
number = input.nextInt();
if (number > max){
max = number;
}
if (number < min){
min = number;
}
}
System.out.println("Highest value: " + max);
System.out.println("Lowest value: " + min);
}
}
Note that max and min are initially set to the first number that the user enters, so there will be no false 0's and no need to MAX_INTor MIN_INT. This in turn makes the loop run once less so terminate at i == 4instead of 5.
请注意， max 和 min 最初设置为用户输入的第一个数字，因此不会出现假 0，也不需要MAX_INTor MIN_INT。这反过来又使循环运行次数减少，因此终止于i == 4而不是 5。
