javascript 在javascript中的二维对象数组中查找值的索引
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Finding index of value in two dimensional array of objects in javascript
提问by RyanP13
I have a 2D array of objects like so:
我有一个二维对象数组，如下所示：
[[{id: 123}, {id: 456}, {id: 789}], [{id: 111}, {id: 222}, {id: 333}], [{id: 444}, {id: 555}, {id: 666}], [{id: 777}]]
I need to find the index of the id at the top array level.
我需要在顶级数组级别找到 id 的索引。
So if i was to search for and id property with value '222' i would expect to return an index of 1.
因此，如果我要搜索值为 '222' 的 id 属性，我希望返回索引为 1。
I have tried the following:
我尝试了以下方法：
var arr = [[{id: 123}, {id: 456}, {id: 789}], [{id: 111}, {id: 222}, {id: 333}], [{id: 444}, {id: 555}, {id: 666}], [{id: 777}]],
len = arr.length
ID = 789;
for (var i = 0; i < len; i++){
for (var j = 0; j < arr[i].length; j++){
for (var key in o) {
if (key === 'id') {
if (o[key] == ID) {
// get index value
}
}
}
}
}
回答by maerics
Wrap your code in a function, replace your comment with return i, fallthrough by returning a sentinel value (e.g. -1):
将您的代码包装在一个函数中，return i通过返回标记值（例如 -1）将您的注释替换为, fallthrough ：
function indexOfRowContainingId(id, matrix) {
for (var i=0, len=matrix.length; i<len; i++) {
for (var j=0, len2=matrix[i].length; j<len2; j++) {
if (matrix[i][j].id === id) { return i; }
}
}
return -1;
}
// ...
indexOfRowContainingId(222, arr); // => 1
indexOfRowContainingId('bogus', arr); // => -1
回答by cliffs of insanity
Since you know you want the id, you don't need the for-inloop.
既然你知道你想要id，你就不需要for-in循环。
Just break the outer loop, and iwill be your value.
只需打破外循环，i就会成为你的价值。
var arr = [[{id: 123}, {id: 456}, {id: 789}], [{id: 111}, {id: 222}, {id: 333}], [{id: 444}, {id: 555}, {id: 666}], [{id: 777}]],
len = arr.length
ID = 789;
OUTER: for (var i = 0; i < len; i++){
for (var j = 0; j < arr[i].length; j++){
if (arr[i][j].id === ID)
break OUTER;
}
}
Or make it into a function, and return i.
或者把它变成一个函数，然后返回i。
