如何迭代 C++ 字符串向量？
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How do I Iterate over a vector of C++ strings?
提问by Simplicity
How do I iterate over this C++ vector?
我如何迭代这个 C++ 向量？
vector<string> features = {"X1", "X2", "X3", "X4"};
vector<string> features = {"X1", "X2", "X3", "X4"};
回答by Rontogiannis Aristofanis
Try this:
尝试这个：
for(vector<string>::const_iterator i = features.begin(); i != features.end(); ++i) {
// process i
cout << *i << " "; // this will print all the contents of *features*
}
If you are using C++11, then this is legal too:
如果您使用的是 C++11，那么这也是合法的：
for(auto i : features) {
// process i
cout << i << " "; // this will print all the contents of *features*
}
回答by Konrad Rudolph
C++11, which you are using if this compiles, allows the following:
如果编译通过，您正在使用的 C++11 允许以下内容：
for (string& feature : features) {
// do something with `feature`
}
This is the range-based forloop.
If you don't want to mutate the feature, you can also declare it as string const&(or just string, but that will cause an unnecessary copy).
如果您不想改变该功能，您也可以将其声明为string const&（或只是string，但这会导致不必要的副本）。
