如何使用 Android 从我的应用程序调用 Wi-Fi 设置屏幕
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How to call Wi-Fi settings screen from my application using Android
提问by Rajendar
Normally I am getting Wi-Fi setting screen on the emulator by clicking on the Settings > Wireless controls > wifi settings. I need to go directly to the Wi-Fi settings screen from my program when pressing on the Wi-Fi button which I have created. Contacts, Call Logs we can handle by using Intent.setData(android.provider.contacts...........). Is there any way to open settings sub-menus/menu from an android program?
Please give me advise or sample code on this.
通常我会通过单击Settings > Wireless controls > wifi settings. 当按下我创建的 Wi-Fi 按钮时，我需要从我的程序直接进入 Wi-Fi 设置屏幕。我们可以使用 Intent.setData(android.provider.contacts...........) 处理联系人、通话记录。有没有办法从android程序打开设置子菜单/菜单？
请给我建议或示例代码。
回答by CommonsWare
Look at android.provider.Settingsfor a series of Intentactions you can use to launch various settings screens (e.g., ACTION_WIFI_SETTINGS).
查看可用于启动各种设置屏幕android.provider.Settings的一系列Intent操作（例如，ACTION_WIFI_SETTINGS）。
EDIT:Add the coding line.
编辑：添加编码行。
startActivity(new Intent(Settings.ACTION_WIFI_SETTINGS));
startActivity(new Intent(Settings.ACTION_WIFI_SETTINGS));
回答by kim myoungho
example
例子
ConnectivityManager manager = (ConnectivityManager)
getSystemService(MainActivity.CONNECTIVITY_SERVICE);
/*
* 3G confirm
*/
Boolean is3g = manager.getNetworkInfo(
ConnectivityManager.TYPE_MOBILE).isConnectedOrConnecting();
/*
* wifi confirm
*/
Boolean isWifi = manager.getNetworkInfo(
ConnectivityManager.TYPE_WIFI).isConnectedOrConnecting();
if (is3g) {
textView.setText("3G");
} else if (isWifi) {
textView.setText("wifi");
} else {
textView.setText("nothing");
// Activity transfer to wifi settings
startActivity(new Intent(Settings.ACTION_WIFI_SETTINGS));
}
回答by Victor Ruiz.
Just have to call an intent with a context, try this:
只需要调用一个带有上下文的意图，试试这个：
startActivity(new Intent(WifiManager.ACTION_PICK_WIFI_NETWORK));
回答by kingston
If you want to do it from the xml file:
如果要从 xml 文件执行此操作：
<PreferenceScreen
xmlns:android="http://schemas.android.com/apk/res/android"
android:key="@string/setting_key"
android:summary="@string/setting_summary"
android:title="@string/setting_title" >
<intent
android:action="android.settings.WIRELESS_SETTINGS"/>
</PreferenceScreen>
This will show an entry in your settings that will call the platform's settings activity
这将在您的设置中显示一个条目，该条目将调用平台的设置活动
回答by Jayakrishnan PM
Here is the code snippet to open wifi settings page
这是打开wifi设置页面的代码片段
Intent intent = new Intent(Intent.ACTION_MAIN, null);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
ComponentName cn = new ComponentName("com.android.settings", "com.android.settings.wifi.WifiSettings");
intent.setComponent(cn);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity( intent);
回答by Rahul Patil
on button click click Listner
在按钮上单击单击 Listner
startActivityForResult(new Intent(Settings.ACTION_WIFI_SETTINGS), 0);
startActivityForResult(new Intent(Settings.ACTION_WIFI_SETTINGS), 0);
回答by Hitesh Sahu
I have implemented it like this in my app:
我已经在我的应用程序中实现了它：
if (Connectivity.isConnected(this)) {
SERVER_IP = Connectivity.getIPAddress(true)
} else {
SERVER_IP = "Not Connected to Network"
Snackbar.make(appRoot, "Not Connected to Network",
Snackbar.LENGTH_INDEFINITE)
.setAction("Open Settings") {
//open network settings
startActivity(Intent(Settings.ACTION_WIFI_SETTINGS))
}.show()
}
}
public static boolean isConnected(Context context) {
NetworkInfo info = Connectivity.getNetworkInfo(context);
return (info != null && info.isConnected());
}
