java 如何在java中每行打印10个数字
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How to print 10 numbers per line in java
提问by Dumbfounded
I have a simple but hard problem and wanted to get your help on this. This is the code:
我有一个简单但困难的问题，希望得到您的帮助。这是代码：
int i = 0;
while (i < 100) {
i++;
System.out.print(i);
}
This is the real issue that I'm having, how do I control the println to display how many numbers per line that I want so I don't just see 100numbers in a row straight?
Btw please if at all possible, don't give me the answer but help me to answer it myself instead.
这是我遇到的真正问题，我如何控制 println 显示我想要的每行多少个数字，这样我就不会直接看到100连续的数字？顺便说一句，如果可能的话，请不要给我答案，而是帮我自己回答。
回答by Sweeper
whileloops? Why not use forloops? They are much better in this kind of situation i.e. when you want to repeat something a known number of times.
while循环？为什么不使用for循环？它们在这种情况下要好得多，即当您想重复某件事已知次数时。
You can use a nested for loop to make this happen:
您可以使用嵌套的 for 循环来实现这一点：
int counter = 0;
for (int i = 0 ; i < 10 ; i++) {
for (int l = 0 j < 10 ; j++) {
System.out.print (counter);
System.out.print (" "); // I think it is best to have spaces between the numbers
counter++;
}
//after printing 10 numbers, go to a new line
System.out.println ();
}
回答by Amit
You could do something like:
你可以这样做：
for(int number = 0; number <= 100; number++) {
if(number % 10 == 0 && number > 0)
System.out.println(number);
else
System.out.print(number + " ");
}
This would create 10 rows of 10 numbers.
这将创建 10 行 10 个数字。
回答by Java noob
Try this one
试试这个
if (i%10==1){
System.out.println("");
}
