(bash) 检查子网范围文件中的 IP
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(bash) check if IP in subnet range file
提问by Stefano Guarella
I've a list of subnet range in a file:
我有一个文件中的子网范围列表：
2.32.0.0-2.47.255.255-255.240.0.0
2.112.0.0-2.119.255.255-255.248.0.0
2.156.0.0-2.159.255.255-255.252.0.0
2.192.0.0-2.199.255.255-255.248.0.0
...
(The file format is: {startip}-{endip}-{netmask})
（文件格式为：{startip}-{endip}-{netmask}）
I need check if an IP is included in one of the subnet in the file.
我需要检查 IP 是否包含在文件的子网之一中。
采纳答案by ShellFish
Try this:
尝试这个：
BEGIN {
FS="."
ex = "false"
split(address, ip, ".")
}
{
split($ awk -v address="2.156.0.5" -f checkIP.awk /path/to/ip/ranges/file
true
$ awk -v address="0.0.0.0" -f checkIP.awk /path/to/ip/ranges/file
false
, range, "[-.]")
for (i=1; i<5; i++) {
if (ip[i] < range[i] || ip[i] > range[i+4])
break;
else if ((ip[i] > range[i] && ip[i] < range[i+4]) || i == 4)
ex = "true"
}
}
END {
print ex
}
Invoke this awk script (checkIP.awk) like this:
checkIP.awk像这样调用这个 awk 脚本 ( )：
echo '127.0.0.0-127.255.255.255-255.0.0.0' | awk -F- '
BEGIN { ip[1] = 127; ip[2] = 0; ip[3] = 0; ip[4] = 1; }
{ split(, startIp, "."); split(, endIp, ".");
for(i = 1; i <= 4; i++) {
if(ip[i] < int(startIp[i]) || ip[i] > int(endIp[i]))
break;
}
if(i == 5)
print "matching line: ", python3 -c 'from ipaddress import ip_address as IP; list(
map(print, ((startip, endip) for startip, endip, _ in
(ip.split("-") for ip in open("tmp/iplist.txt"))
if IP(startip) < IP("127.0.0.1") < IP(endip))))'
; }'
回答by myaut
You may use awkfor that:
您可以awk为此使用：
import sys
from ipaddress import ip_address as IP
ip = IP(sys.argv[1])
with open(sys.argv[2]) as f:
for line in f:
startIp, endIp, _ = line.split('-')
if IP(startIp) < ip < IP(endIp):
print(line)
IP for searching is initially set as array in BEGIN-clause as array. Each line is compared in for-cycle and if each octet laying between startIpand endIp, "matching line" is printed.
用于搜索的 IP 最初在 BEGIN 子句中设置为数组作为数组。每行都在 for-cycle 中进行比较，如果每个八位字节都位于startIp和之间endIp，则会打印“匹配行”。
Some Python 3 gibberish relying on ipaddress module from 3.3 (available for 2.6/2.7:
一些 Python 3 胡言乱语依赖于 3.3 中的 ipaddress 模块（可用于 2.6/2.7：
$ python3 ipcheck.py 127.0.0.1 iplist.txt
Which is actually one-liner version for following script:
这实际上是以下脚本的单行版本：
awk -F- -v arg='2.158.1.2' 'function ipval(arg) {
split(arg, arr, ".");
s=0;
for (i=1; i<=length(arr); i++)
s += arr[i] * (10**(6-i));
return s
}
ipval(arg) >= ipval() && ipval(arg) <= ipval()' file
2.156.0.0-2.159.255.255-255.252.0.0
Which can be used like that:
可以这样使用：
function ipval()
{
RES=`awk -F- -v arg="" '{
split(arg, arr, ".");
s=0;
for (i=1; i<=length(arr); i++) { s += arr[i] * (256**(4-i)); }
print s
}' <<< '' `
return $RES
}
read -p "IP:" IP
ipval "$IP"
echo "RES=$RES"
回答by anubhava
You can use this awk script:
你可以使用这个 awk 脚本：
##代码##ipvalconverts given ip address to a numeric value so that it can be compared easily using arithmetical operator.
ipval将给定的 ip 地址转换为数值，以便可以使用算术运算符轻松进行比较。
回答by hvillemoes
I find this variant of the above script more useful:
我发现上述脚本的这个变体更有用：
##代码##