如何使用 Java 处理 Selenium WebDriver 中的弹出窗口
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How to handle Pop-up in Selenium WebDriver using Java
提问by Niyati
I want to handle sign-in part in rediff.com, but the below code doesn't work for that:
我想在 rediff.com 中处理登录部分，但下面的代码对此不起作用：
driver.get("http://www.rediff.com/");
WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
sign.click();
String myWindowHandle = driver.getWindowHandle();
driver.switchTo().window(myWindowHandle);
WebElement email_id= driver.findElement(By.xpath("//*[@id='signin_info']/a[1]"));
email_id.sendKeys("hi");
If myWindowHandleis not the correct string, then let me know how to get the pop-up Window name, because I can't find the name of the pop-up window.
如果myWindowHandle不是正确的字符串，请告诉我如何获取弹出窗口名称，因为我找不到弹出窗口的名称。
采纳答案by LINGS
To switch to a popup window, you need to use getWindowHandles()and iterate through them.
要切换到弹出窗口，您需要使用getWindowHandles()并遍历它们。
In your code you are using getWindowHandle()which will give you the parent window itself.
在您正在使用的代码中getWindowHandle()，它将为您提供父窗口本身。
String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;
Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();
while (iterator.hasNext()){
subWindowHandler = iterator.next();
}
driver.switchTo().window(subWindowHandler); // switch to popup window
// Now you are in the popup window, perform necessary actions here
driver.switchTo().window(parentWindowHandler); // switch back to parent window
回答by Hemanth
Do not make the situation complex. Use IDif they are available.
不要把情况复杂化。ID如果可用，请使用它们。
driver.get("http://www.rediff.com");
WebElement sign = driver.findElement(By.linkText("Sign in"));
sign.click();
WebElement email_id= driver.findElement(By.id("c_uname"));
email_id.sendKeys("hi");
回答by Niyati
I found the solution for the above program, which had the goal of signing in to http://rediff.com
我找到了上述程序的解决方案，其目标是登录http://rediff.com
public class Handle_popupNAlert
{
public static void main(String[] args ) throws InterruptedException
{
WebDriver driver= new FirefoxDriver();
driver.get("http://www.rediff.com/");
WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
sign.click();
Set<String> windowId = driver.getWindowHandles(); // get window id of current window
Iterator<String> itererator = windowId.iterator();
String mainWinID = itererator.next();
String newAdwinID = itererator.next();
driver.switchTo().window(newAdwinID);
System.out.println(driver.getTitle());
Thread.sleep(3000);
driver.close();
driver.switchTo().window(mainWinID);
System.out.println(driver.getTitle());
Thread.sleep(2000);
WebElement email_id= driver.findElement(By.xpath("//*[@id='c_uname']"));
email_id.sendKeys("hi");
Thread.sleep(5000);
driver.close();
driver.quit();
}
}
回答by Satheesh kumar
//get the main handle and remove it
//whatever remains is the child pop up window handle
String mainHandle = driver.getWindowHandle();
Set<String> allHandles = driver.getWindowHandles();
Iterator<String> iter = allHandles.iterator();
allHandles.remove(mainHandle);
String childHandle=iter.next();
回答by ER.swatantra
You can handle popup window or alert box:
您可以处理弹出窗口或警报框：
Alert alert = driver.switchTo().alert();
alert.accept();
You can also decline the alert box:
您还可以拒绝警告框：
Alert alert = driver.switchTo().alert();
alert().dismiss();
回答by Sandip
When the toastr message poped up on the screen of firefox. the below tag was displayed in fire bug.
当 Firefox 的屏幕上弹出 toastr 消息时。下面的标签显示在 fire bug 中。
<div class="toast-message">Invalid Credentials, Please check Password</div>.
I took the screenshot at that time. And did the below changes in selenium java code.
我当时截图了。并在 selenium java 代码中做了以下更改。
String alertText = "";
WebDriverWait wait = new WebDriverWait(driver, 5);
wait.until(ExpectedConditions.visibilityOfElementLocated(By.className("toast-message")));
WebElement toast1 = driver.findElement(By.className("toast-message"));
alertText = toast1.getText();
System.out.println( alertText);
And my issue of toastr popup got resolved.
我的 toastr 弹出问题得到了解决。
回答by ankush deol
public void Test(){
WebElement sign = fc.findElement(By.xpath(".//*[@id='login-scroll']/a"));
sign.click();
WebElement LoginAsGuest=fc.findElement(By.xpath(".//*[@id='guest-login-option']"));
LoginAsGuest.click();
WebElement email_id= fc.findElement(By.xpath(".//*[@id='guestemail']"));
email_id.sendKeys("[email protected]");
WebElement ContinueButton=fc.findElement(By.xpath(".//*[@id='contibutton']"));
ContinueButton.click();
}
回答by Manasis Mishra
You can use the below code inside your code when you get any web browser pop-up alert message box.
当您收到任何 Web 浏览器弹出警报消息框时，您可以在代码中使用以下代码。
// Accepts (Click on OK) Chrome Alert Browser for RESET button.
Alert alertOK = driver.switchTo().alert();
alertOK.accept();
//Rejects (Click on Cancel) Chrome Browser Alert for RESET button.
Alert alertCancel = driver.switchTo().alert();
alertCancel.dismiss();
回答by user3150673
String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;
Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();
subWindowHandler = iterator.next();
driver.switchTo().window(subWindowHandler); // switch to popup window
// Now you are in the popup window, perform necessary actions here
driver.switchTo().window(parentWindowHandler); // switch back to parent window
