C++ 一个类有多少个默认方法?
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How Many default methods does a class have?
提问by Armen Tsirunyan
Sorry, this might seem simple, but somebody asked me this, and I don't know for certain.
抱歉,这可能看起来很简单,但有人问过我这个问题,我不确定。
An empty C++ class comes with what functions?
一个空的 C++ 类带有什么功能?
Constructor, Copy Constructor, Assignment, Destructor?
构造函数、复制构造函数、赋值、析构函数?
Is that it? Or are there more?
是这样吗?或者还有更多?
回答by Armen Tsirunyan
In C++03 there are 4:
在 C++03 中有 4 个:
Default constructor: Declared only if no user-defined constructor is declared. Defined when used
Copy constructor- declared only if the user hasn't declared one. Defined if used
Copy-assignment operatorsame as above
Destructorsame as above
默认构造函数:仅当未声明用户定义的构造函数时才声明。使用时定义
复制构造函数- 仅当用户未声明时才声明。定义如果使用
复制赋值运算符同上
析构函数同上
In C++11 there are two more:
在 C++11 中还有两个:
- Move constructor
- Move-assignment operator
- 移动构造函数
- 移动赋值运算符
It is also possible that the compiler won't be able to generate some of them. For example, if the class contains, for example, a reference (or anything else that cannot be copy-assigned), then the compiler won't be able to generate a copy-assignment operator for you. For more information read this
编译器也可能无法生成其中的一些。例如,如果类包含一个引用(或其他任何不能被复制赋值的东西),那么编译器就不能为你生成一个复制赋值运算符。有关更多信息,请阅读此
回答by Martin York
If I define the following class
如果我定义以下类
class X
{};
The compiler will define the following methods:
编译器将定义以下方法:
X::X() {} // Default constructor. It takes zero arguments (hence default).
X::~X() {} // Destructor
X::X(X const& rhs) {}; // Copy constructor
X& operator=(X const& rhs)
{return *this;} // Assignment operator.
Note:
The default constructor is not built if ANYconstructor is defined.
The other methods are not built if the user defines an alternative.
注意:
如果定义了任何构造函数,则不会构建默认构造函数。
如果用户定义了替代方法,则不会构建其他方法。
What is slightly more interesting is the default implementation when we have members and a base:
更有趣的是当我们有成员和基时的默认实现:
class Y: public X
{
int a; // POD data
int* b; // POD (that also happens to be a pointer)
Z z; // A class
};
// Note: There are two variants of the default constructor.
// Both are used depending on context when the compiler defined version
// of the default constructor is used.
//
// One does `default initialization`
// One does `zero initialization`
// Objects are zero initialized when
// They are 'static storage duration'
// **OR** You use the braces when using the default constructor
Y::Y() // Zero initializer
: X() // Zero initializer
, a(0)
, b(0)
, z() // Zero initializer of Z called.
{}
// Objects are default initialized when
// They are 'automatic storage duration'
// **AND** don't use the braces when using the default constructor
Y::Y()
:X // Not legal syntax trying to portray default initialization of X (base class)
//,a // POD: uninitialized.
//,b // POD: uninitialized.
,z // Not legal syntax trying to portray default initialization of z (member)
{}
//
// Note: It is actually hard to correctly zero initialize a 'automatic storage duration'
// variable (because of the parsing problems it tends to end up a a function
// declaration). Thus in a function context member variables can have indeterminate
// values because of default initialization. Thus it is always good practice to
// to initialize all members of your class during construction (preferably in the
// initialization list).
//
// Note: This was defined this way so that the C++ is backward compatible with C.
// And obeys the rule of don't do more than you need too (because we want the C++
// code to be as fast and efficient as possible.
Y::Y(Y const& rhs)
:X(rhs) // Copy construct the base
,a(rhs.a) // Copy construct each member using the copy constructor.
,b(rhs.b) // NOTE: The order is explicitly defined
,z(rhs.z) // as the order of declaration in the class.
{}
Y& operator=(Y const& rhs)
{
X::operator=(rhs); // Use base assignment operator
a = rhs.a; // Use the assignment operator on each member.
b = rhs.b; // NOTE: The order is explicitly defined
z = rhs.z; // as the order of declaration in the class.
return(*this);
}
Y::~Y()
{
Your Code first
}
// Not legal code. Trying to show what happens.
: ~z()
, ~b() // Does nothing for pointers.
, ~a() // Does nothing for POD types
, ~X() ; // Base class destructed last.
回答by Victor Stepanov
Just to expand on Armen Tsirunyan answerhere are the signatures for the methods:
只是为了扩展Armen Tsirunyan的答案,这里是方法的签名:
// C++03
MyClass(); // Default constructor
MyClass(const MyClass& other); // Copy constructor
MyClass& operator=(const MyClass& other); // Copy assignment operator
~MyClass(); // Destructor
// C++11 adds two more
MyClass(MyClass&& other) noexcept; // Move constructor
MyClass& operator=(MyClass&& other) noexcept; // Move assignment operator
回答by rvkreddy
Default methods assigned by compiler for a empty class:
编译器为空类分配的默认方法:
http://cplusplusinterviews.blogspot.sg/2015/04/compiler-default-methods.html
http://cplusplusinterviews.blogspot.sg/2015/04/compiler-default-methods.html
回答by Prasoon Saurav
Is that it?
是这样吗?
Yes thats it.
对,就是那样。
Compiler generates by default
编译器默认生成
- A default constructor
- A copy constructor
- A copy assignment operator
- A destructor
- 默认构造函数
- 复制构造函数
- 复制赋值运算符
- 析构函数
for a class
为一个班级
You can see the default constructor, the copy constructor and the assignment operator being generated by default when you use -ast-dump
option of Clang
当您使用-ast-dump
Clang 的选项时,您可以看到默认生成的默认构造函数、复制构造函数和赋值运算符
prasoon@prasoon-desktop ~ $ cat empty.cpp && clang++ -cc1 -ast-dump empty.cpp
class empty
{};
int main()
{
empty e;
empty e2 = e;
{
empty e3;
e3 = e;
}
}
typedef char *__builtin_va_list;
class empty {
class empty;
inline empty() throw(); //default c-tor
//copy c-tor
inline empty(empty const &) throw() (CompoundStmt 0xa0b1050 <empty.cpp:1:7>)
//assignment operator
inline empty &operator=(empty const &) throw() (CompoundStmt 0xa0b1590 <empty.cpp:1:7>
(ReturnStmt 0xa0b1578 <col:7>
(UnaryOperator 0xa0b1558 <col:7> 'class empty' prefix '*'
(CXXThisExpr 0xa0b1538 <col:7> 'class empty *' this))))
};