使用 jquery ajax 发布一个数组
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post an array using jquery ajax
提问by Daniel
I am trying to do something fairly simple but I can't seem to find the solution. I want to post a multi-dimensional array to a php page using jQuery's .ajax function, but I can't seem to serialize the array properly.
我正在尝试做一些相当简单的事情，但似乎找不到解决方案。我想使用 jQuery 的 .ajax 函数将多维数组发布到 php 页面，但我似乎无法正确序列化该数组。
The code is as follows
代码如下
var dataToSend = new Array();
dataToSend["page"] = location.href;
dataToSend["data"] = new Array();
var dataindex = 0;
jQuery(".myclass").each(function(){
dataToSend["data"][dataindex]=new Array();
dataToSend["data"][dataindex]["selector"] = unique_selector(jQuery(this), "");
dataToSend["data"][dataindex]["contents"] = jQuery(dataToSend["data"][dataindex]["selector"]).html();
});
jQuery.ajax({
type: 'POST',
url: "/main/save.php",
data: JSON.stringify(dataToSend),
dataType: "json",
success: function(data){alert(data);}
});
basically I am not sure how to properly pass the dataToSend array. Right now firebug show the post as empty even though the array is loaded with all kinds of good stuff.
基本上我不确定如何正确传递 dataToSend 数组。现在，即使数组加载了各种好东西，firebug 仍将帖子显示为空。
Thanks,
谢谢，
Daniel
丹尼尔
回答by jerone
You're defining new Array();, but you're using them as new Object(). Try using objects.
您正在定义new Array();，但您将它们用作new Object(). 尝试使用对象。
Try this:
尝试这个：
var dataToSend = {
page: location.href,
data: []
};
var dataindex = 0;
jQuery(".myclass").each(function(){
var temp = unique_selector(jQuery(this), "");
dataToSend.data[dataindex++] = {
selector: temp,
contents: jQuery(temp).html()
};
});
jQuery.ajax({
type: 'POST',
url: "/main/save.php",
data: JSON.stringify(dataToSend),
dataType: "json",
success: function(data){ alert(data); }
});
回答by slandau
Taken from the PHP help pages:
取自 PHP 帮助页面：
you may have multidimensional array in form inputs
您可能在表单输入中有多维数组
HTML Example:
HTML 示例：
<input name="data[User][firstname]" type="text" />
<input name="data[User][lastname]" type="text" />
...
Inside php script after submit you can access the individual element like so:
提交后在 php 脚本中，您可以像这样访问单个元素：
$firstname = $_POST['data']['User']['firstname'];
...
回答by Mukesh Agarwal
Use
用
data: { '': dataToSend }
I used this in a similar scenario and it worked like charm...
我在类似的场景中使用了它，它的作用就像魅力......
