java Jpa 组合键可为空的列
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Jpa composite key nullable columns
提问by Miguel Ping
I'm using Hibernate's JPA impl to model some tables. I'm having trouble mapping a table that:
我正在使用 Hibernate 的 JPA impl 对一些表进行建模。我在映射一个表时遇到问题:
- Has no primary key
- Has a unique index on 4 columns, 3 of which can be nullable
- 没有主键
- 在 4 列上有唯一索引,其中 3 列可以为空
I tried to hack it and define the index as a composite Id, but since some columns are nullable this is not working properly. Is this possible with JPA/Hibernate?
我试图破解它并将索引定义为复合 Id,但由于某些列可以为空,因此无法正常工作。这可以用 JPA/Hibernate 实现吗?
Thanks
谢谢
采纳答案by Kevin Crowell
A work arround is... You should implements your own UserType implementation and treats the null value to return a representative Object for this.
一个工作是......您应该实现自己的 UserType 实现并处理空值以为此返回一个代表对象。
Look my example. The field is a nullable numeric, so my implementation is:
看我的例子。该字段是一个可为空的数字,所以我的实现是:
Looks like in HBM file:
在 HBM 文件中看起来像:
<key-property name="fieldName" type="mypackage.forUserTypes.DefaultLongType">
<column name="FIELD_NAME" precision="10" scale="0" />
</key-property>
...In Java:
...在 Java 中:
public class DefaultLongType implements UserType {
private static final long serialVersionUID = 1L;
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#assemble(java.io.Serializable, java.lang.Object)
*/
public Object assemble(Serializable cached, Object owner)
throws HibernateException {
return null;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#deepCopy(java.lang.Object)
*/
public Object deepCopy(Object value) throws HibernateException {
return null;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#disassemble(java.lang.Object)
*/
public Serializable disassemble(Object value) throws HibernateException {
return null;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#equals(java.lang.Object, java.lang.Object)
*/
public boolean equals(Object x, Object y) throws HibernateException {
if (x == y) return true;
if (x == null) return false;
return x.equals(y);
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#hashCode(java.lang.Object)
*/
public int hashCode(Object x) throws HibernateException {
return x == null ? 0 : x.hashCode();
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#isMutable()
*/
public boolean isMutable() {
return false;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#nullSafeGet(java.sql.ResultSet, java.lang.String[], java.lang.Object)
*/
public Object nullSafeGet(ResultSet rs, String[] names, Object owner)
throws HibernateException, SQLException {
final long value = rs.getLong(names[0]);
if (rs.wasNull()) {
return new Long(Long.MIN_VALUE);
}
return new Long(value);
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#nullSafeSet(java.sql.PreparedStatement, java.lang.Object, int)
*/
public void nullSafeSet(PreparedStatement st, Object value, int index)
throws HibernateException, SQLException {
Long l = (Long) value;
if (l == null || l.longValue() == Long.MIN_VALUE) {
st.setNull(index, Types.NUMERIC);
}
else {
st.setLong(index, l.longValue());
}
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#replace(java.lang.Object, java.lang.Object, java.lang.Object)
*/
public Object replace(Object original, Object target, Object owner)
throws HibernateException {
return original;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#returnedClass()
*/
public Class returnedClass() {
return Long.class;
}
/* (non-Javadoc)
* @see org.hibernate.usertype.UserType#sqlTypes()
*/
public int[] sqlTypes() {
final int[] args = { Types.NUMERIC };
return args;
}
}
}
回答by Kevin Crowell
It seems that the column that is not nullable should be your primary key. No parts of a composite key should ever be nullable.
似乎不可为空的列应该是您的主键。复合键的任何部分都不应该可以为空。
You will need to take the nullable properties and place them outside of your primary/composite key.
您需要获取可为空的属性并将它们放在主键/复合键之外。
Also, this looks like a duplicate of Hibernate mapping a composite key with null valueswhich came up as #3 when I googled "null composite key".
此外,这看起来像是Hibernate的副本映射一个具有空值的复合键,当我在 google 上搜索“空复合键”时,该复合键出现在 #3 中。

