javascript 获取AngularJS中指定的url的html内容
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getting the html content of the url specified in AngularJS
提问by clearScreen
I am using the $http.get('url') to get the content present in the 'url' present. The html in 'url' is as follows
我正在使用 $http.get('url') 来获取存在于 'url' 中的内容。'url'中的html如下
<html>
<head></head>
<body>
<pre style = "word-wrap: break-word; white-space: pre-wrap;">
<!-- content is present here -->
</pre>
</body>
</html>
When I make a $http.get to this url, I get some data and the required content
当我对这个 url 做一个 $http.get 时，我得到了一些数据和所需的内容
GET /TYPE=abvd HTTP 1.1
content required
.0.1234.123 Safari /123.12
Referer: //url of the webpage calling this function
Accept-Encoding:
...............
How do I get rid of this extra information and receive only the content? (I know we can just parse the response but is there a better way of doing it? )
我如何摆脱这些额外信息并只接收内容？（我知道我们可以只解析响应，但有没有更好的方法呢？）
EDIT: The data response I got was seen in google chrome, when I run the same script in IE10, I get the only the "html content" as desired. Why does this difference occur and how do I make process it?
编辑：我得到的数据响应是在谷歌浏览器中看到的，当我在 IE10 中运行相同的脚本时，我只得到了所需的“html 内容”。为什么会出现这种差异，我该如何处理？
回答by Drakes
$http.getreturns an HttpPromise, and from it you can get the underlying data like so:
$http.get返回一个HttpPromise，您可以从中获取基础数据，如下所示：
$http.get('url').then(function(response) {
html = response.data;
});
To get even more useful data, you can expand this like so:
要获得更多有用的数据，您可以像这样扩展它：
$http.get('url').then(
// success handler
function(response) {
var data = response.data,
status = response.status,
header = response.header,
config = response.config;
},
// error handler
function(response) {
var data = response.data,
status = response.status,
header = response.header,
config = response.config;
});
Demo:JSBin
演示：JSBin
Edit:If there are still HTML issues, you can look into $sce.trustAsHtml(html)or PhantomJS with references:
编辑：如果仍然存在 HTML 问题，您可以查看$sce.trustAsHtml(html)或 PhantomJS 参考：
