在 C/C++ 中迭代字母表
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Iterate alphabet in C/C++
提问by user1735120
How do I translate the following code into C/C++?
如何将以下代码翻译成 C/C++？
string alphabet = "abcdefghijklmnopqrstuvwxyz";
foreach(char c in alphabet)
{
// Do something with the letter
}
I want to loop into the alphabet and print each character when a button is pressed. Like how you input a character when using an Xbox/PS3controller. You scroll into the entire set of alphabet and then press a button for input.
我想循环到字母表中并在按下按钮时打印每个字符。就像使用Xbox/ PS3控制器时输入字符的方式一样。您滚动到整个字母表中，然后按一个按钮进行输入。
Basically this is being used in a microcontroller (mbed) environment. I just need to know how to create the correct logic in looping in C/C++.
基本上这是在微控制器 ( mbed) 环境中使用的。我只需要知道如何在 C/C++ 循环中创建正确的逻辑。
回答by KitsuneYMG
#include <string>
#include <algorithm>
void doSomething( const char& );
int main() {
std::string alphabet = "abcdefghijklmnopqrstuvwxyz";
std::for_each( alphabet.begin(), alphabet.end(), &doSomething);
}
or
或者
#include <string>
#include <boost/foreach.hpp>
int main() {
std::string alphabet = "abcdefghijklmnopqrstuvwxyz";
BOOST_FOREACH( char c, alphabet) {
//do something
}
}
With C++2011
使用 C++2011
#include <string>
#include <algorithm>
int main() {
std::string alphabet = "abcdefghijklmnopqrstuvwxyz";
std::for_each( alphabet.begin(), alphabet.end(),[](const char& c){ /*do something*/} );
}
or even
甚至
#include <string>
int main() {
std::string alphabet = "abcdefghijklmnopqrstuvwxyz";
for( char c : alphabet) {
//do something
}
}
EDIT: You mentioned in your edit the desire for this to work in an embedded environment
编辑：您在编辑中提到希望在嵌入式环境中工作
int main() {
const char* alphabet = "abcdefghijklmnopqrstuvwxyz";
for( char* ptr = alphabet; *ptr!='int main() {
for( char l = 'a'; l<='z'; ++l) {
//do something (l)
}
}
'; ++ptr) {
//do something (*ptr)
}
}
Edit2:
编辑2：
If you knowthat you're using something like ASCII
如果你知道你正在使用类似 ASCII 的东西
for (auto c : alphabet)
{
//do something with letter
}
回答by Mike Seymour
You should decide which language you're using; C and C++ are two distinct languages, so there isn't a single answer for both languages.
您应该决定使用哪种语言；C 和 C++ 是两种不同的语言，因此这两种语言都没有统一的答案。
In modern C++:
在现代 C++ 中：
for (size_t i = 0; i < alphabet.size(); ++i)
{
char c = alphabet[i];
//do something with letter
}
In old-school C++, there are various options; the least ugly is probably
在老式 C++ 中，有多种选择；最不丑的可能是
char const * alphabet = "abcdefghijklmnopqrstuvwxyz";
In C, it depends what stringis, since there is no standard type with that name. If it's a conventional zero-terminated character array:
在 C 中，这取决于是什么string，因为没有具有该名称的标准类型。如果它是一个传统的以零结尾的字符数组：
for (char const * p = alphabet; *p; ++p)
{
char c = *p;
// do something with letter
}
then something like:
然后是这样的：
#include <iostream>
#include <string>
int main ()
{
std::string str ("abcdefghijklmnopqrstuvwxyz");
for ( std::string::iterator itr=str.begin(); it!=str.end(); ++it)
{
//do something
}
return 0;
}
