php 如何在laravel 5中使用Storage facade获取文件路径？
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How to get file path using Storage facade in laravel 5?
提问by daviestar
I've been experimenting using the new Flysystem integration with Laravel 5. I am storing 'localised' paths to the DB, and getting the Storage facade to complete the path. For example I store screenshots/1.jpgand using
我一直在尝试使用新的 Flysystem 与 Laravel 5 的集成。我将“本地化”路径存储到数据库，并获取存储外观以完成路径。例如我存储screenshots/1.jpg和使用
Storage::disk('local')->get('screenshots/1.jpg')
or
或者
Storage::disk('s3')->get('screenshots/1.jpg')
I can retrieve the same file on different disks.
我可以在不同的磁盘上检索相同的文件。
getretrieves the file contents, but I am hoping to use it in my views like this:
get检索文件内容，但我希望在我的视图中使用它，如下所示：
<img src="{{ Storage::path('screenshots/1.jpg') }}" />
but path, or anything able to retrieve the full path is not available (as far as I can see). So how can I return the full path? Or, I'm wondering if this is by design? If so, why am I not supposed to be able to get the full path? Or, am I going about this completely the wrong way?
但是路径或任何能够检索完整路径的东西都不可用（据我所知）。那么我怎样才能返回完整路径呢？或者，我想知道这是否是设计使然？如果是这样，为什么我不能获得完整路径？或者，我是否完全以错误的方式处理这个问题？
采纳答案by Pere Joan Martorell
Edit: Solution for L5.2+
编辑：L5.2+ 的解决方案
There's a better and more straightforward solution.
有一个更好、更直接的解决方案。
Use Storage::url($filename)to get the full path/URL of a given file. Note that you need to set S3as your storage filesystem in config/filesystems.php: 'default' => 's3'
使用Storage::url($filename)得到给定文件的完整路径/ URL。请注意，您需要在以下位置设置S3为您的存储文件系统config/filesystems.php：'default' => 's3'
Of course, you can also do Storage::disk('s3')->url($filename)in the same way.
当然，你也可以Storage::disk('s3')->url($filename)用同样的方法。
As you can see in config/filesystems.phpthere's also a parameter 'cloud' => 's3'defined, that refers to the Cloud filesystem. In case you want to mantain the storage folder in the local server but retrieve/store some files in the cloud use Storage::cloud(), which also has the same filesystem methods, i.e. Storage::cloud()->url($filename).
如您所见，config/filesystems.php还'cloud' => 's3'定义了一个参数，它指的是云文件系统。如果您想在本地服务器中维护存储文件夹但在云中检索/存储一些文件，请使用Storage::cloud()，它也具有相同的文件系统方法，即Storage::cloud()->url($filename).
The Laravel documentation doesn't mention this method, but if you want to know more about it you can check its source code here.
Laravel 文档没有提到这个方法，但是如果你想了解更多关于它的信息，你可以在这里查看它的源代码。
回答by shock_gone_wild
The Path to your Storage disk would be :
存储磁盘的路径为：
$storagePath = Storage::disk('local')->getDriver()->getAdapter()->getPathPrefix()
I don't know any shorter solutions to that...
我不知道任何更短的解决方案......
You could share the $storagePath to your Views and then just call
您可以将 $storagePath 共享到您的视图，然后调用
$storagePath."/myImg.jpg";
回答by Bilal Gultekin
This method exists since Laravel 5.4, you can get it by:
这个方法从 Laravel 5.4 开始就存在，你可以通过以下方式获得它：
$path = Storage::disk('public')->path($filename);
回答by daviestar
This is how I got it to work - switching between s3 and local directory paths with an environment variable, passing the path to all views.
这就是我让它工作的方式 - 使用环境变量在 s3 和本地目录路径之间切换，将路径传递给所有视图。
In .env:
在 .env 中：
APP_FILESYSTEM=local or s3
S3_BUCKET=BucketID
In config/filesystems.php:
在 config/filesystems.php 中：
'default' => env('APP_FILESYSTEM'),
In app/Providers/AppServiceProvider:
在 app/Providers/AppServiceProvider 中：
public function boot()
{
view()->share('dynamic_storage', $this->storagePath());
}
protected function storagePath()
{
if(Storage::getDefaultDriver() == 's3') {
return Storage::getDriver()
->getAdapter()
->getClient()
->getObjectUrl(env('S3_BUCKET'), '');
}
return URL::to('/');
}
回答by filius
First get file url/link then path, as below:
首先获取文件 url/link 然后是路径，如下：
$url = Storage::disk('public')->url($filename);
$path = public_path($url);
回答by fsasvari
If you just want to display storage (disk) path use this:
如果您只想显示存储（磁盘）路径，请使用以下命令：
Storage::disk('local')->url('screenshots/1.jpg'); // storage/screenshots/1.jpg
Storage::disk('local')->url(''): // storage
Also, if you are interested, I created a package (https://github.com/fsasvari/laravel-uploadify) just for Laravel so you can use all those fields on Eloquent model fields:
另外，如果您有兴趣，我为 Laravel创建了一个包（https://github.com/fsasvari/laravel-uploadify），这样您就可以在 Eloquent 模型字段上使用所有这些字段：
$car = Car::first();
$car->upload_cover_image->url();
$car->upload_cover_image->name();
$car->upload_cover_image->basename();
$car->upload_cover_image->extension();
$car->upload_cover_image->filesize();
回答by manix
Well, weeks ago I made a very similiar question (Get CDN url from uploaded file via Storage): I wanted the CDN url to show the image in my view (as you are requiring ).
好吧，几周前我提出了一个非常相似的问题（通过存储从上传的文件中获取 CDN 网址）：我希望 CDN 网址在我的视图中显示图像（如您所需要）。
However, after review the package API I confirmed that there is no way do this task. So, my solution was avoid using flysystem. In my case, I needed to play with RackSpace. So, finally decide to create my use package and make my own storage package using The PHP SDK for OpenStack.
但是，在查看包 API 后，我确认无法执行此任务。所以，我的解决方案是避免使用flysystem. 就我而言，我需要玩 RackSpace。所以，最终决定使用The PHP SDK for OpenStack创建我的使用包并制作我自己的存储包。
By this way, you have full access for functions that you need like getPublicUrl()in order to get the public URL from a cdn container:
通过这种方式，您可以完全访问您需要的功能，getPublicUrl()以便从 cdn 容器中获取公共 URL：
/** @var DataObject $file */
$file = \OpenCloud::container('cdn')->getObject('screenshots/1.jpg');
// $url: https://d224d291-8316ade.ssl.cf1.rackcdn.com/screenshots/1.jpg
$url = (string) $file->getPublicUrl(UrlType::SSL);
In conclusion, if need to take storage service to another level, then flysystemis not enough. For localpurposes, you can try @nXu's solution
总之，如果需要将存储服务提升到另一个层次，那flysystem是不够的。出于local目的，您可以尝试@nXu 的解决方案
回答by Arvind Bhardwaj
If you need absolute URL of the file, use below code:
如果您需要文件的绝对 URL，请使用以下代码：
$file_path = \Storage::url($filename);
$url = asset($file_path);
// Output: http://example.com/storage/filename.jpg
回答by Marc Garcia
Another solution I found is this:
我发现的另一个解决方案是：
Storage::disk('documents')->getDriver()->getConfig()->get('url')
Will return the url with the base path of the documents Storage
将返回带有文档存储基本路径的 url
回答by Mevlüt?zdemir
Store method:
存储方法：
public function upload($img){
$filename = Carbon::now() . '-' . $img->getClientOriginalName();
return Storage::put($filename, File::get($img)) ? $filename : '';
}
Route:
路线：
Route::get('image/{filename}', [
'as' => 'product.image',
'uses' => 'ProductController@getImage',
]);
Controller:
控制器：
public function getImage($filename)
{
$file = Storage::get($filename);
return new Response($file, 200);
}
View:
看法：
<img src="{{ route('product.image', ['filename' => $yourImageName]) }}" alt="your image"/>
