python中带有变量的新行
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new line with variable in python
提问by user6234753
When I use "\n"in my printfunction it gives me a syntax error in the following code
当我"\n"在我的print函数中使用时，它在下面的代码中给了我一个语法错误
from itertools import combinations
a=[comb for comb in combinations(range(1,96+1),7) if sum(comb) == 42]
print (a "\n")
Is there any way to add new line in each combination?
有没有办法在每个组合中添加新行？
回答by ShadowRanger
The printfunction already adds a newline for you, so if you just want to print followed by a newline, do (parens mandatory since this is Python 3):
该print函数已经为您添加了一个换行符，因此如果您只想打印后跟一个换行符，请执行（括号是必需的，因为这是 Python 3）：
print(a)
If the goal is to print the elements of aeach separated by newlines, you can either loop explicitly:
如果目标是打印a由换行符分隔的每个元素，您可以显式循环：
for x in a:
print(x)
or abuse star unpacking to do it as a single statement, using septo split outputs to different lines:
或滥用星形解包将其作为单个语句执行，sep用于将输出拆分为不同的行：
print(*a, sep="\n")
If you want a blank line between outputs, not just a line break, add end="\n\n"to the first two, or change septo sep="\n\n"for the final option.
如果你想输出之间添加一个空白行，而不仅仅是一个换行符，end="\n\n"改变了前两个，或sep到sep="\n\n"了最后的选项。
回答by PfunnyGuy
Two possibilities:
两种可能：
print "%s\n" %a
print a, "\n"
回答by Garrett R
This will work for you:
这对你有用：
I used 1,2...6 in my example and 2 length tuples with a combination sum of 7.
我在我的例子中使用了 1,2...6 和 2 个长度为 7 的元组。
from itertools import combinations
a=["{0}\n".format(comb) for comb in combinations(range(1,7),2) if sum(comb) == 7]
print(a)
for thing in a:
print(thing)
Output
输出
['(1, 6)\n', '(2, 5)\n', '(3, 4)\n']
(1, 6)
(2, 5)
(3, 4)
回答by fastlan
for me in the past something like print("\n",a) works.
过去对我来说，像 print("\n",a) 这样的东西是有效的。
