C# 字母数字单词的正则表达式，长度必须为 6 个字符
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regex for alphanumeric word, must be 6 characters long
提问by
What is the regex for a alpha numeric word, at least 6 characters long (but at most 50).
字母数字单词的正则表达式是什么，至少 6 个字符长（但最多 50 个）。
回答by Jeremy Ruten
With PCRE regex you could do this:
使用 PCRE 正则表达式，您可以这样做：
/[a-zA-Z0-9]{6,50}/
It would be very hard to do in regex without the min/max quantifiers so hopefully your language supports them.
如果没有最小/最大量词，在正则表达式中很难做到，所以希望你的语言支持它们。
回答by chroder
/[a-zA-Z0-9]{6,50}/
You can use word boundaries at the beginning/end (\b) if you want to actually match a word within text.
如果要实际匹配文本中的单词，可以在开头/结尾 (\b) 使用单词边界。
/\b[a-zA-Z0-9]{6,50}\b/
回答by Peter Boughton
\b\w{6,50}\b
\wis any 'word' character - depending on regex flavour it might be just [a-z0-9_] or it might include others (e.g. accented chars/etc).
\w是任何“单词”字符 - 根据正则表达式的风格，它可能只是 [a-z0-9_] 或者可能包括其他字符（例如重音字符/等）。
{6,50}means between 6 and 50 (inclusive)
{6,50}表示 6 到 50（含）之间
\bmeans word boundary (ensuring the word does not exceed the 50 at either end).
\b表示单词边界（确保单词两端不超过 50）。
After re-reading, it appears that what you want do is ensure the entire text matches? If so...
重读之后，看来你要做的就是确保整个文本匹配？如果是这样的话...
^\w{6,50}$
