Spring 数据 JPA java.lang.IllegalArgumentException:不是实体
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/10872740/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring data JPA java.lang.IllegalArgumentException: Not an entity
提问by Hasitha
I have created spring data JPA sample project. I used eclips for this. There are two projects, one is domain object project which has only annotated entity classes. Other project is actual spring data jpa project and it has a dependency for the project one. Actually it gets domain project entity classes via maven dependency.
我已经创建了弹簧数据 JPA 示例项目。我为此使用了 eclips。有两个项目,一个是只有注释实体类的域对象项目。另一个项目是实际的 spring 数据 jpa 项目,它对项目一有依赖。实际上它通过 maven 依赖获取域项目实体类。
Project 1 : hrm-domain
项目一:hrm-domain
Entity class :
实体类:
package com.hrm.ws.data.domain;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Inheritance;
import javax.persistence.InheritanceType;
import javax.persistence.Table;
@Entity(name = "Employee")
@Table(name = "employee")
@Inheritance(strategy = InheritanceType.JOINED)
public class Employee {
protected long id;
protected String firstName;
protected String lastName;
/**
* Gets the value of the id property.
*
*/
@Id
@Column(name = "id", scale = 0)
@GeneratedValue(strategy = GenerationType.AUTO)
public long getId() {
return id;
}
Project 2 : hrm-ws-service
项目 2:hrm-ws-service
persistance-context.xml
持久化上下文.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd">
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driverClassName}"/>
<property name="url" value="${jdbc.url}"/>
<property name="username" value="${jdbc.username}"/>
<property name="password" value="${jdbc.password}"/>
</bean>
<jpa:repositories base-package="com.hrm.ws.data.repository" />
<bean id="employeeDao" class="com.hrm.ws.data.repository.EmployeeRepositoryImpl"/>
<bean class="org.springframework.orm.jpa.JpaTransactionManager" id="transactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />
</property>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="generateDdl" value="${jdbc.generateDdl}" />
<property name="showSql" value="${jdbc.showSql}"/>
</bean>
</property>
<property name="persistenceUnitName" value="jpa.sample" />
</bean>
</beans>
So the setup for my packages is as follows:
所以我的包的设置如下:
src/main/java - contains the spring repository
src/main/java - 包含 spring 存储库
src/main/resources - contains application context
src/main/resources - 包含应用程序上下文
src/test/java - contains unit tests
src/test/java - 包含单元测试
And dependency for the project 1 (hrm-domain)
和项目 1 的依赖(hrm-domain)
My problem is when I run this project I am getting error as follows:
我的问题是当我运行这个项目时,我收到如下错误:
... 38 more
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'employeeRepository': FactoryBean threw exception on object creation; nested exception is java.lang.IllegalArgumentException: Not an entity: class com.hrm.ws.data.domain.Employee
at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.doGetObjectFromFactoryBean(FactoryBeanRegistrySupport.java:149)
at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.getObjectFromFactoryBean(FactoryBeanRegistrySupport.java:102)
at org.springframework.beans.factory.support.AbstractBeanFactory.getObjectForBeanInstance(AbstractBeanFactory.java:1429)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:190)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.findAutowireCandidates(DefaultListableBeanFactory.java:844)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:786)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:703)
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:474)
... 40 more
**Caused by: java.lang.IllegalArgumentException: Not an entity: class** com.hrm.ws.data.domain.Employee
at org.hibernate.ejb.metamodel.MetamodelImpl.entity(MetamodelImpl.java:160)
at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:52)
at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:61)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:145)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:83)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:66)
at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:146)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:120)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:39)
at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.doGetObjectFromFactoryBean(FactoryBeanRegistrySupport.java:142)
... 48 more
I am wondering about this issue, because when I put domain object (Employee.java) in my spring project it self rather separate jar it works fine. This issue only happens it gives as a separate jar. If any one has experience about scenario like that please give me a help.
我想知道这个问题,因为当我将域对象 (Employee.java) 放在我的 spring 项目中时,它自己而不是单独的 jar 它工作正常。这个问题只发生在它作为一个单独的罐子里。如果有人对这样的场景有经验,请给我帮助。
回答by higuaro
I also had the same problem. Mine was that I didn't supply the packagesToScanproperty in the entityManagerFactorybean, so Spring couldn't load the Entities. Check out the emfbean declaration in your spring configuration xml. The following is a EMF declaration I hope it could help you to get rid the error:
我也有同样的问题。我的是我没有packagesToScan在entityManagerFactorybean 中提供属性,所以 Spring 无法加载实体。查看emfspring 配置 xml 中的bean 声明。以下是 EMF 声明,希望它可以帮助您摆脱错误:
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
<property name="packagesToScan" value="com.hrm.ws.data.domain" />
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />
</property>
</bean>
回答by threejeez
You're not scanning the com.hrm.ws.data.domain package for beans annotated with @Entity so the spring container has no knowledge of your entities and therefore producing an exception. Add the following lines to your persistance-context.xml config file:
您没有在 com.hrm.ws.data.domain 包中扫描带有 @Entity 注释的 bean,因此 spring 容器不知道您的实体,因此会产生异常。将以下行添加到您的 persistance-context.xml 配置文件中:
<context:annotation-config />
<context:component-scan base-package="com.hrm.ws.data.domain" />
You'll also need to change your root xml element as follows so it the context elements are recognized:
您还需要按如下方式更改根 xml 元素,以便识别上下文元素:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
And, if you haven't already, add the spring-context dependency to your pom file.
而且,如果您还没有,请将 spring-context 依赖项添加到您的 pom 文件中。
回答by Mahender Yadav
Use one of the following option :-
使用以下选项之一:-
context:component-scan base-package="Your Base Package Name" in spring.xml file
set packagesToScan property on the entityManagerFactory
use persistence.xml and list all entities there.
context:component-scan base-package="Your Base Package Name" in spring.xml 文件
在 entityManagerFactory 上设置 packagesToScan 属性
使用persistence.xml 并列出那里的所有实体。

