java 如何输入一个句子，以便程序将句子识别为单个单词？
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how to i input a sentence so that the program will recognize the sentence as a single word?
提问by Wai Loon II
lets say i input : 'dog is mammal'
假设我输入：“狗是哺乳动物”
i would like to search for this sentence in a text document. How do i do this in java ?
我想在文本文档中搜索这句话。我如何在 java 中做到这一点？
System.out.println("Please enter the query :");
Scanner scan2 = new Scanner(System.in);
String word2 = scan2.nextLine();
String[] array2 = word2.split(" ");
this code snippet accepts the string 'dog is mammal' and process each tokens separately.
此代码片段接受字符串“狗是哺乳动物”并分别处理每个标记。
For example : 'dog is mammal'
例如：“狗是哺乳动物”
dog
狗
>
>
>
>
is
是
>
>
>
>
mammal
哺乳动物
>
>
>
>
i would like to process the input as
我想将输入处理为
dog is mammal
狗是哺乳动物
>
>
>
>
I doesnt want it to process it separately. I wanted it to process it as a single string and look for matches. Can anyone let me know where i am lacking ?
我不希望它单独处理它。我希望它将它作为单个字符串处理并查找匹配项。任何人都可以让我知道我的不足之处吗？
回答by Peter Lawrey
If you want to process the String as a single piece of text, why split up the string into words. I would just use the original word2you have which is the whole text AFAICS
如果要将 String 作为单个文本进行处理，为什么要将字符串拆分为单词。我只会使用word2您拥有的原始文本，即整个文本 AFAICS
EDIT: If I run
编辑：如果我跑
System.out.println("Please enter the query :");
Scanner scan2 = new Scanner(System.in);
String word2 = scan2.nextLine();
System.out.println(">"+word2+"<");
I get
我得到
Please enter the query :
dog is mammal
>dog is mammal<
The input is not broken up by word.
输入不会被单词分解。
回答by Nirmal- thInk beYond
find word2directly in file, and if you has parsed whole file then use string indexof(word2)in file
word2直接在文件中查找，如果您已经解析了整个文件，则indexof(word2)在文件中使用字符串
回答by bezmax
Simply concatinate them all while reading:
阅读时只需将它们连接起来：
public String scanSentence() {
Scanner scan2 = new Scanner(System.in);
StringBuilder builder = new StringBuilder();
String word2;
//I do not know how you want to terminate input, so let it be END word.
//If you will be reading from file - change it to "while ((word2 = scan2.nextLine()) != null)"
//Notice the "trim" part
while (!(word2 = scan2.nextLine().trim()).equals("END")) {
builder.append(word2);
builder.append(" ");
}
return builder.toString().trim();
}
