javascript 如何为未选中的复选框序列化数组?
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How can I serializeArray for unchecked checkboxes?
提问by BrunoLM
How can I modify this exampleso it can get values from checkboxes that aren't checked?
如何修改此示例以便它可以从未选中的复选框中获取值?
I want all checkboxes to have a value, if it hasn't been checked I want to get its value as false
.
我希望所有复选框都有一个值,如果尚未选中,我想将其值设为false
.
<input type="checkbox" name="Check01" value="true" />
<input type="checkbox" name="Check02" value="true" checked="checked" />
Default behavior
默认行为
$("form").serializeArray();
// [Check02 = true]
Expected behavior
预期行为
$("form").serializeArray();
// [Check01 = false, Check02 = true]
采纳答案by Pointy
It's probably easiest to just do it yourself:
自己做可能最简单:
var serialized = $('input:checkbox').map(function() {
return { name: this.name, value: this.checked ? this.value : "false" };
});
If there are other inputs, then you could serialize the form, and then find the unchecked checkboxes with something like the above and append that result to the first array.
如果还有其他输入,那么您可以序列化表单,然后使用类似上述内容找到未选中的复选框,并将该结果附加到第一个数组。
回答by ShankarSangoli
回答by tang wei
you can use this get unchecked values
您可以使用此获取未选中的值
$.fn.serializeObject = function () {
var o = {};
var a = this.serializeArray();
$.each(a, function () {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
var $radio = $('input[type=radio],input[type=checkbox]',this);
$.each($radio,function(){
if(!o.hasOwnProperty(this.name)){
o[this.name] = '';
}
});
return o;
};
回答by Ben
another option is to just look at the source code for serializeArray and remove (or modify) the call to filter. I Just took that function and created a new one called serializeArrayAll like this:
另一种选择是查看 serializeArray 的源代码并删除(或修改)对过滤器的调用。我刚刚使用了该函数并创建了一个名为 serializeArrayAll 的新函数,如下所示:
$.fn.serializeArrayAll = function() {
var rCRLF = /\r?\n/g;
return this.map(function(){
return this.elements ? jQuery.makeArray( this.elements ) : this;
})
/* this is what is excluding the unchecked checkboxes (and also other disabled options)
.filter(function(){
return this.name && !this.disabled &&
( this.checked || rselectTextarea.test( this.nodeName ) ||
rinput.test( this.type ) );
})
*/
.map(function( i, elem ){
var val = jQuery( this ).val();
return val == null ?
null :
jQuery.isArray( val ) ?
jQuery.map( val, function( val, i ){
return { name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
}) :
{ name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
}).get();
};
};
回答by tothemario
Using the jQuery plugin serializeJSON, you can use the data-unchecked-value
attribute to specify the value when unchecked:
使用 jQuery 插件serializeJSON,您可以使用该data-unchecked-value
属性在未选中时指定值:
<input type="checkbox" name="Check01" value="true" data-unchecked-value="false" />
<input type="checkbox" name="Check02" value="true" data-unchecked-value="false" checked="checked" />
JavaScript:
JavaScript:
$('input').serializeJSON({ parseBooleans: true });
// returns => { 'Check01' : false, 'Check02' : true }
回答by Johnny Oshika
you can add a hidden false value for every checkbox:
您可以为每个复选框添加一个隐藏的 false 值:
<input type="checkbox" name="Check01" value="true" /><input name="Check01" type="hidden" value="false" />
<input type="checkbox" name="Check02" value="true" checked="checked" /><input name="Check02" type="hidden" value="false" />
You will only get "false" values for unchecked checkboxes and both "true" and "false" for checked checkboxes, so you can remove the duplicates like this:
对于未选中的复选框,您只会获得“false”值,而对于选中的复选框,您将获得“true”和“false”值,因此您可以像这样删除重复项:
var params = {};
$.each($('form').serializeArray(), function (index, value) {
params[value.name] = params[value.name] ? params[value.name] || value.value : value.value;
});
console.log(params); // outputs: {"Check01":"false","Check02":"true"}
回答by SNag
Here's how I implemented a simple override of $.serializeArray
which fixes the default serialization behaviour for checkboxes, and default behaviour is retained for all other types.
这是我如何实现一个简单的覆盖,$.serializeArray
它修复了复选框的默认序列化行为,并保留了所有其他类型的默认行为。
In the code below, missed checkboxes are injected into the original serialized array. Checkbox state is returned as "true"
(instead of "on"
) or "false"
depending on if it is checked
or not.
在下面的代码中,丢失的复选框被注入到原始序列化数组中。复选框状态返回为"true"
(而不是"on"
)或"false"
取决于它是否为checked
。
(function ($) {
var _base_serializeArray = $.fn.serializeArray;
$.fn.serializeArray = function () {
var a = _base_serializeArray.apply(this);
$.each(this.find("input"), function (i, e) {
if (e.type == "checkbox") {
e.checked
? a[i].value = "true"
: a.splice(i, 0, { name: e.name, value: "false" })
}
});
return a;
};
})(jQuery);
You could customize this to return "on"/"off"
or true/false
.
您可以将其自定义为 return"on"/"off"
或true/false
。
Update: Fixed code based on bug found by @shyammakwana.me.
更新:基于@shyammakwana.me 发现的错误修复了代码。
回答by shyammakwana.me
@SNag's answerworker almost 99% just with little bit correction. Change below line
@SNag 的回答人员几乎 99% 只是稍作修正。更改线下
from :
从 :
$.each(this, function (i, e) {
to:
到:
$.each(this.find('input'), function (i, e) {
Explanation: As this was not working because this
returned form element. So on form .each
won't give us all input elements inside form. So I did this correction and it worked like charm.
说明:因为这不起作用,因为this
返回了表单元素。因此,表单.each
不会为我们提供表单内的所有输入元素。所以我做了这个更正,它很有魅力。
回答by yk4ever
You can append unchecked checkbox data to .serializeArray
result:
您可以将未选中的复选框数据附加到.serializeArray
结果中:
var formData = $("#mybaseelement").serializeArray();
$('#mybaseelement input[type="checkbox"]:not(:checked)').each(function(i, e) {
formData.push({name: e.getAttribute("name"), value: false});
});
This is the least invasive solution I can come up with.
这是我能想出的侵入性最小的解决方案。
回答by picomp
I made my own new solution based on the answers by @Pointy, @Ben, and the original jQuery code. The answer from @Pointy had odd behavior that returned contexts for checkboxes, this fixes that problem. The answer from @Ben was also not acting properly because it always returned checkbox = on
even if it was unchecked.
我根据@Pointy、@Ben 和原始 jQuery 代码的答案制作了自己的新解决方案。@Pointy 的答案有奇怪的行为,返回复选框的上下文,这解决了这个问题。@Ben 的回答也没有正确运行,因为checkbox = on
即使未选中它也总是返回。
$.fn.serializeArrayWithCheckboxes = function() {
var rCRLF = /\r?\n/g;
return this.map(function(){
return this.elements ? jQuery.makeArray( this.elements ) : this;
})
.map(function( i, elem ){
var val = jQuery( this ).val();
if (val == null) {
return val == null
//next 2 lines of code look if it is a checkbox and set the value to blank
//if it is unchecked
} else if (this.type == "checkbox" && this.checked == false) {
return { name: this.name, value: this.checked ? this.value : ""}
//next lines are kept from default jQuery implementation and
//default to all checkboxes = on
} else {
return jQuery.isArray( val ) ?
jQuery.map( val, function( val, i ){
return { name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
}) :
{ name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
}
}).get();
};