Python 如何获取用户权限？
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How to get user permissions?
提问by Nips
I want to retrieve all permission for user as list of premission id's but:
我想检索用户的所有权限作为权限 ID 列表，但是：
user.get_all_permissions()
give me list of permission names. How to do it?
给我权限名称列表。怎么做？
采纳答案by Paulo Bu
The key is get the permission objects like this:
关键是获取这样的权限对象：
from django.contrib.auth.models import Permission
permissions = Permission.objects.filter(user=user)
and there you can access the idproperty like this:
在那里您可以id像这样访问该属性：
permissions[0].id
If you want the list (id, permission_name)do the following:
如果您想要列表，(id, permission_name)请执行以下操作：
perm_tuple = [(x.id, x.name) for x in Permission.objects.filter(user=user)]
Hope it helps!
希望能帮助到你！
回答by DRC
to get all the permissions of a given user, also the permissions associated with a group this user is part of:
获取给定用户的所有权限，以及与该用户所属的组关联的权限：
from django.contrib.auth.models import Permission
def get_user_permissions(user):
if user.is_superuser:
return Permission.objects.all()
return user.user_permissions.all() | Permission.objects.filter(group__user=user)
回答by Shihabudheen K M
we can get user permission from user objects directly into a list like this
我们可以从用户对象中直接获取用户权限到这样的列表中
perm_list = user_obj.user_permissions.all().values_list('codename', flat=True)
Try this....
尝试这个....
回答by Moritz
This is an routine to query for the Permission objects returned by user.get_all_permissions()in a single query.
这是一个例程，用于查询user.get_all_permissions()单个查询中返回的 Permission 对象。
from functools import reduce
from operator import or_
from django.db.models import Q
from django.contrib.auth.models import Permission
def get_user_permission_objects(user):
user_permission_strings = user.get_all_permissions()
if len(user_permission_strings) > 0:
perm_comps = [perm_string.split('.', 1) for perm_string in user_permission_strings]
q_query = reduce(
or_,
[Q(content_type__app_label=app_label) & Q(codename=codename) for app_label, codename in perm_comps]
)
return Permission.objects.filter(q_query)
else:
return Permission.objects.none()
Alternatively, querying Permission directly:
或者，直接查询权限：
from django.db.models import Q
from django.contrib.auth.models import Permission
def get_user_permission_objects(user):
if user.is_superuser:
return Permission.objects.all()
else:
return Permission.objects.filter(Q(user=user) | Q(group__user=user)).distinct()
回答by Amey Dhuri
from django.contrib.auth.models import Permission
permissions = Permission.objects.filter(user=user)
permissions[0].id
