如何使用 List<Object> 将对象值设置为 Java 中的模型类？
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How to set object value using List<Object> to a model class in java?
提问by Ke Vin
how do add each property value in my model using List? Here is what i do
如何使用 List 在我的模型中添加每个属性值？这是我所做的
here is my object : Item.java
这是我的对象： Item.java
public class Item {
private String code;
private String name;
private Integer qty;
// skip the getter setter
}
here is how i want to add the value from another class
这是我想从另一个类中添加值的方式
List<Item> sBarang = new ArrayList<Item>();
sBarang.add("");
How do I add each property value my Item.java?
如何将每个属性值添加到我的 Item.java？
What I can do is something like this :
我能做的是这样的：
Item mItem = new Item();
mItem .setCode("101");
mItem .setName("Hammer");
mItem .setQty(10);
采纳答案by Elliott Frisch
Unless I'm missing something you just need to add your mItemto your List. Like
除非我遗漏了一些东西，否则您只需mItem要将您的List. 喜欢
Item mItem = new Item(); // <-- instantiate a new Item.
mItem.setCode("101");
mItem.setName("Hammer");
mItem.setQty(10);
sBarang.add(mItem); // <-- add it to your List<Item>.
You could also create a new Itemconstructor that looks something like
您还可以创建一个Item看起来像的新构造函数
public Item(String code, String name, Integer qty) {
this.code = code;
this.name = name;
this.qty = qty;
}
and then use a single line add like
然后使用单行添加
sBarang.add(new Item("101", "Hammer", 10));
回答by Patrick Chan
Make a constructor for your convenience.
为方便起见，制作一个构造函数。
public class Item {
public Item(String code, String name, int qty){
this.code=code;
this.name=name;
this.qty=qty;
}
private String code;
private String name;
private Integer qty;
//skip the getter setter
}
Since then, you can add new "Item" object easily by
从那时起，您可以通过以下方式轻松添加新的“项目”对象
sBarang.add(new Item("101","Hammer",10));
回答by CorbinMc
sBarang.add("")is not going to work. Your trying to add a Stringto a list containing only Itemobjects.
sBarang.add("")不会工作。您尝试将 a 添加String到仅包含Item对象的列表中。
The second half of your post sounds like you're looking for a more efficient way to assign values to the fields of your Iteminstance. Do this by adding a constructor to your class. That will look like this:
您帖子的后半部分听起来像是在寻找一种更有效的方法来为Item实例的字段赋值。通过向类中添加构造函数来完成此操作。看起来像这样：
public class Item {
public Item (String startCode, String startName, int startQty) {
this.code = startCode;
this.name = startName;
this.qty = startQty;
}
...
}
Initialize your item like this: Item myItem = new Item("101", "Hammer", 10);
像这样初始化你的项目： Item myItem = new Item("101", "Hammer", 10);
Add it to your list like this: sBarang.add(myItem);
像这样将其添加到您的列表中： sBarang.add(myItem);
Or use the one-liner: sBarang.add(new Item("101", "Hammer", 10));
或者使用单线： sBarang.add(new Item("101", "Hammer", 10));
回答by user11036750
Item m= new Item();
m.Set_Code("101");
m.set_Name("Hammer");
m.set_Qty(10);
s_barang . add(m);
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