Android 如何解决路径中的异常非法字符？
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How to solve the exception Illegal character in path?
提问by sivaraj
I am displaying images from an URL using XML parsing and some images are displaying very well, but sometimes I get exception like
我正在使用 XML 解析显示来自 URL 的图像，并且一些图像显示得很好，但有时我会遇到类似的异常
Illegal character in path at index 113: http://www.theblacksheeponline.com/party_img/thumbspps/12390867930_15951_186997180114_709920114_4296270_6115611_n[1].jpg
索引 113 路径中的非法字符：http: //www.theblacksheeponline.com/party_img/thumbspps/12390867930_15951_186997180114_709920114_4296270_61151611_n[
How to solve this problem, please provide some sample code...
如何解决这个问题，请提供一些示例代码...
回答by mrjohn
Special characters need escaping such as %5Bfor [ and %5Dfor ]
特殊字符需要转义，例如%5Bfor [ 和%5Dfor ]
You can use the java.net.URLEncoderto encode the URL as in
您可以使用java.net.URLEncoder对 URL 进行编码，如
java.net.URLEncoderURLEncoder.encode(myurltoencode,"UTF-8");
This will not just fix the [ or ] but also other encoding issues
这不仅可以解决 [ 或 ] 问题，还可以解决其他编码问题
回答by Arthur Rizzo
use this escape code for [ %5Band for the closing ] use %5D
将此转义码用于 [ %5B和结束 ] 使用%5D
回答by AlikElzin-kilaka
This did the trick:
这做到了：
URL url = new URL("http://www.theblacksheeponline.com/party_img/thumbspps/12390867930_15951_186997180114_709920114_4296270_6115611_n[1].jpg");
URI uri = new URI(url.getProtocol(), url.getUserInfo(), url.getHost(), url.getPort(), url.getPath(), url.getQuery(), url.getRef());
URLEncoder is used for web forms application/x-www-form-urlencodedmime-type - not http network addresses.
URLEncoder 用于 web 表单application/x-www-form-urlencodedmime-type - 而不是 http 网络地址。
回答by Alexander Farber
The modern way to handle this problem in a Java program or servlet would be to use OWASP.
在 Java 程序或 servlet 中处理这个问题的现代方法是使用OWASP。
For example, if using Maven to build your program, add the following to your pom.xml file
例如，如果使用 Maven 构建您的程序，请将以下内容添加到您的 pom.xml 文件中
<properties>
<owasp.version>1.2.1</owasp.version>
</properties>
<dependencies>
<dependency>
<groupId>org.owasp.encoder</groupId>
<artifactId>encoder</artifactId>
<version>${owasp.version}</version>
</dependency>
</dependencies>
And then call the Encode.forHtmlmethod:
然后调用Encode.forHtml方法：
String safeStr= Encode.forHtml(str);
