C++ 'y' 未在此范围内声明，
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/19371693/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
'y' was not declared in this scope,
提问by Yuriy Mikhailovich
I had a lot of problems with this project, I figured out a lot. but this one I can't
我在这个项目中遇到了很多问题，我想出了很多。但这个我不能
Here I have some calculations, and then I need this "y" variable to pass to next .cpp
这里我有一些计算，然后我需要这个“y”变量传递给下一个 .cpp
#include <iostream>
#include <math.h>
using namespace std;
int Ing(int number, float y)
{
y = 0;
float Lngth = 0;
for(; number != 0; number /= 10, Lngth++);
float n = nearbyint(sqrt(Lngth));
y = Lngth * pow(10, n);
return (y);
}
here is the next .cpp
这是下一个 .cpp
#include <iostream>
#include "InitialGuess.h"
#include <math.h>
using namespace std;
int SquareRoot(int number, int th)
{
float iGuess = Ing(y);
float x = iGuess;
for (int k=1; k< th; ++k)
{
x = (x + (number / x ))/2;
}
cout<<x;
return (x);
}
But on compilation It gives me error that "y" was not declared in this scope. Where I've made a mistake?
但是在编译时它给了我一个错误，即未在此范围内声明“y”。我哪里做错了？
Thank you
谢谢
回答by Mike Makuch
On this line
在这条线上
float iGuess = Ing(y);
you don't have y declared, which causes the error. What value do you want to pass to Ing()?
你没有 y 声明，这会导致错误。你想传递给 Ing() 什么值？
You've got 2 parameters defined for Ing(int, float) but only calling it with one.
你已经为 Ing(int, float) 定义了 2 个参数，但只用一个来调用它。
回答by 0x499602D2
y = 0;
should be
应该
int y = 0;
because yhas not yet be declared at this point and you are defining a variable.
因为此时y尚未声明并且您正在定义一个变量。
