java 将 JSONArray 转换为 arrayList
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Convert JSONArray to arrayList
提问by azelix
I'm trying to convert a JSONArraywhich looks like this :
我正在尝试转换一个JSONArray看起来像这样的：
{"output":["name":"Name3","URI":"Value3"},{"name":"Name5","URI":"Value5"},{"name":"Name4","URI":"Value4"}]}
Into an arrayList so for example the output of Arr[0][0]will be Name3
进入arrayList 所以例如输出Arr[0][0]将是Name3
I have tried this solution:
我试过这个解决方案：
if (outputs!= null) {
int len = outputs.length();
for (int j=0;j<len;j++){
list.add(outputs.get(j).toString());
}
}
for (String str : list) {
System.out.println("Item is: " + str);
}
But I get the full row : {"name":"Name3","URI":"Value3"}
但我得到了整行： {"name":"Name3","URI":"Value3"}
How can I get each object of my JSONArray?
我怎样才能得到我的每个对象JSONArray？
采纳答案by MaxZoom
Aazelix, your Json output seem to be missing opening array bracket. Its correct form is listed below:
Aazelix，您的 Json 输出似乎缺少开放数组括号。其正确形式如下：
{"output":[{"name":"Name3","URI":"Value3"},{"name":"Name5","URI":"Value5"},{"name":"Name4","URI":"Value4"}]}
As for the conversion to POJO
至于转换为POJO
List<MyObj> list = new ArrayList<>();
if (outputs!= null) {
int len = outputs.length();
for (int i=0; i<len; i++) {
JSONObject o = (JSONObject) outputs.get(i);
list.add(new MyObj(o.getString('name'), o.getString('URL')));
}
}
System.out.println("There is " + list.size() + " objects.");
public static final class MyObj {
final String name;
final String url;
public MyObj(String name, String url) {
this.name = name;
this.url = url;
}
}
回答by Dmitry Ginzburg
It is not specified, which JSON parser do you use, so I suppose you can choose right now and I'll suggest using Gsonas such.
它没有指定，你使用哪个 JSON 解析器，所以我想你现在可以选择，我会建议使用Gson它。
The better solution for deserializing such a structures is creating a special class for each structure, for example:
反序列化此类结构的更好解决方案是为每个结构创建一个特殊的类，例如：
public class NameURIPair {
private String name;
private String URI;
// getters
}
Then your JSON can be deserialized into a class, which holds the resulting Listin it:
然后您的 JSON 可以反序列化为一个类，其中包含结果List：
public class Data {
private List<NameURIPair> output;
// getter
}
// ...
Data data = new Gson(stringData, Data.class);
Since you've requested the other way, you still can get just the parsed JSON into JsonElementwith JsonParser
由于您以另一种方式请求，您仍然可以将解析的 JSON 转换JsonElement为JsonParser
JsonElement root = new JsonParser().parse(stringData);
Although I won't give you the full solution not to appreciate this kind of solutions :-)
虽然我不会给你完整的解决方案不欣赏这种解决方案:-)
