C语言 使用 C 将字符数组转换为字符串
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Convert char array to string use C
提问by ARTAS
I need to convert a char array to string. Something like this:
我需要将字符数组转换为字符串。像这样的东西：
char array[20];
char string[100];
array[0]='1';
array[1]='7';
array[2]='8';
array[3]='.';
array[4]='9';
...
I would like to get something like that:
我想得到这样的东西：
char string[0]= array // where it was stored 178.9 ....in position [0]
回答by Mike
You're saying you have this:
你说你有这个：
char array[20]; char string[100];
array[0]='1';
array[1]='7';
array[2]='8';
array[3]='.';
array[4]='9';
And you'd like to have this:
你想要这个：
string[0]= "178.9"; // where it was stored 178.9 ....in position [0]
You can't have that. A char holds 1 character. That's it. A "string" in C is an array of characters followed by a sentinel character (NULL terminator).
你不能有那个。一个字符包含 1 个字符。就是这样。C 中的“字符串”是一个字符数组，后跟一个标记字符（NULL 终止符）。
Now if you want to copy the first x characters out of arrayto stringyou can do that with memcpy():
现在，如果你想第一个X字符复制出来array到string你可以做到这一点memcpy()：
memcpy(string, array, x);
string[x] = 'char * strncpy(char * destination, const char * source, size_t num);
';
回答by Alex DiCarlo
Assuming arrayis a character array that does not end in \0, you will want to use strncpy:
假设array是一个不以 结尾的字符数组\0，您将需要使用strncpy：
strncpy(string, array, 20);
string[20] = 'char array[20]; char string[100];
array[0]='1'; array[1]='7'; array[2]='8'; array[3]='.'; array[4]='9'; array[5]='##代码##';
strcpy(string, array);
printf("%s\n", string);
'
like so:
像这样：
##代码##Then stringwill be a null terminated C string, as desired.
然后string将是一个空终止的 C 字符串，根据需要。
回答by David Ranieri
You can use strcpybut remember to end the array with '\0'
您可以使用strcpy但请记住以'\0'
