将 c 样式字符串转换为 c++ 样式字符串
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converting c style string to c++ style string
提问by assassin
Can anyone please tell me how to convert a C style string (i.e a char* ) to a c++ style string (i.e. std::string) in a C++ program?
谁能告诉我如何在 C++ 程序中将 C 样式字符串（即 char* ）转换为 C++ 样式字符串（即 std::string）？
Thanks a lot.
非常感谢。
回答by John Weldon
std::stringcan take a char *as a constructorparameter, and via a number of operators.
std::string可以将 achar *作为构造函数参数，并通过多个运算符。
char * mystr = "asdf";
std::string mycppstr(mystr);
or for the language lawyers
或语言律师
const char * mystr = "asdf";
std::string mycppstr(mystr);
回答by zaharpopov
char* cstr = //... some allocated C string
std::string str(cstr);
The contents of cstrwill be copied to str.
的内容cstr将被复制到str.
This can be used in operations too like:
这也可以用于操作：
std::string concat = somestr + std::string(cstr);
Where somestris already `std::string``
哪里somestr已经是 `std::string`
回答by codaddict
You can make use of the stringclass constructorwhich takes a char*as argument.
您可以使用将 a作为参数的string类构造char*函数。
char *str = "some c style string";
string obj(str);
回答by quamrana
Another way to do the conversion is to call a function which takes a const std::string&as a parameter:
进行转换的另一种方法是调用一个将 aconst std::string&作为参数的函数：
void foo(const std::string& str);
void bar()
{
char* str= ...
foo(str);
}
I think its a lot more tidy to do the conversion at a function call boundary.
我认为在函数调用边界进行转换要整洁得多。
