java 使用正则表达式获取子字符串
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Get substring with regular expression
提问by StefanE
I'm stuck with regular expression and Java.
我坚持使用正则表达式和 Java。
My input string that looks like this:
我的输入字符串如下所示：
"EC: 132/194 => 68% SC: 55/58 => 94% L: 625"
I want to read out the first and second values (that is, 132and 194) into two variables. Otherwise the string is static with only numbers changing.
我想将第一个和第二个值（即132和194）读出到两个变量中。否则字符串是静态的，只有数字在变化。
回答by KeatsPeeks
I assume the "first value" is 132, and the second one 194.
我假设“第一个值”是 132 ，第二个是 194。
This should do the trick:
这应该可以解决问题：
String str = "EC: 132/194 => 68% SC: 55/58 => 94% L: 625";
Pattern p = Pattern.compile("^EC: ([0-9]+)/([0-9]+).*$");
Matcher m = p.matcher(str);
if (m.matches())
{
String firstValue = m.group(1); // 132
String secondValue= m.group(2); // 194
}
回答by Andreas Dolk
You can solve it with String.split():
您可以使用以下方法解决它String.split()：
public String[] parse(String line) {
String[] parts = line.split("\s+");
// return new String[]{parts[3], parts[7]}; // will return "68%" and "94%"
return parts[1].split("/"); // will return "132" and "194"
}
or as a one-liner:
或作为单线：
String[] values = line.split("\s+")[1].split("/");
and
和
int[] result = new int[]{Integer.parseInt(values[0]),
Integer.parseInt(values[1])};
回答by stark
If you were after 68 and 94, here's a pattern that will work:
如果你在 68 岁和 94 岁之后，这里有一个有效的模式：
String str = "EC: 132/194 => 68% SC: 55/58 => 94% L: 625";
Pattern p = Pattern.compile("^EC: [0-9]+/[0-9]+ => ([0-9]+)% SC: [0-9]+/[0-9]+ => ([0-9]+)%.*$");
Matcher m = p.matcher(str);
if (m.matches()) {
String firstValue = m.group(1); // 68
String secondValue = m.group(2); // 94
System.out.println("firstValue: " + firstValue);
System.out.println("secondValue: " + secondValue);
}
