C# 将 bool 值更改为与初始值相反的值
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Changing bool values to opposite of the initial value
提问by user1046403
This maybe sound strange to you but I'm too lazy to write everytime like
这对你来说可能听起来很奇怪，但我懒得每次都写
if (threadAlive)
{
threadAlive = false;
}
else
{
threadAlive = true;
}
isn't there is something like int++ or int-- to change bool value to opposite of its value?
是不是有像 int++ 或 int-- 之类的东西可以将 bool 值更改为与其值相反的值？
回答by p.s.w.g
Just do this:
只需这样做：
threadAlive = !threadAlive;
回答by piokuc
Very simple:
很简单：
threadAlive = ! threadAlive;
回答by ouah
Use the !operator:
使用!运算符：
bool b = true;
b = !b; // b is now false
回答by Kyle_the_hacker
The logical negation operator !is a unary operator that negates its operand. It is defined for booland returns trueif and only if its operand is falseand falseif and only if its operand is true:
逻辑否定运算符!是一个否定其操作数的一元运算符。当且仅当其操作数为且当且仅当其操作数为 时，它被定义bool并返回：truefalsefalsetrue
threadAlive = !threadAlive;
回答by xanatos
Yes, there is!
就在这里！
threadAlive ^= true;
(this is a C# joke, in the most general case it won't work in C/C++/Javascript (it couldwork in C/C++/Javascript depending on some conditions), but it's true! ^is the xor operator)
（这是一个 C# 笑话，在最一般的情况下它不会在 C/C++/Javascript 中工作（它可以在 C/C++/Javascript 中工作，具体取决于某些条件），但这是真的！^是异或运算符）
回答by Avram Tudor
You can't overload operatorsfor basic types if that's what you're looking for.
As everyone else mentioned already, this is by far your best option:
正如其他人已经提到的，这是迄今为止您最好的选择：
threadAlive = !threadAlive;
You can however, although is something I would never recommend, create your own booltype and overload the ++or whatever operator you wish to invert your value.
但是，虽然我永远不会推荐，但您可以创建自己的bool类型并重载++或您希望反转值的任何运算符。
The following code is something that should neverbe used anyway:
以下代码无论如何都不应该使用：
public class MyBool
{
bool Value;
public MyBool(bool value)
{
this.Value = value;
}
public static MyBool operator ++(MyBool myBoolean)
{
myBoolean.Value = !myBoolean.Value;
return myBoolean;
}
}
You can also create your own extension method but that won't be be a better way either.
您也可以创建自己的扩展方法，但这也不是更好的方法。
