Javascript 按属性对 JSON 数组进行排序的通用方法

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时间:2020-08-24 04:27:20  来源:igfitidea点击:

Generic way of sorting JSON array by attribute

javascriptarraysjsonsorting

提问by userPassingBy

I found out how to sort a JSON array at http://www.devcurry.com/2010/05/sorting-json-array.html

我在http://www.devcurry.com/2010/05/sorting-json-array.html找到了如何对 JSON 数组进行排序

Now I want to sort it in a generic way; so that my sorting function knows which attribute to sort by.

现在我想以通用的方式对其进行排序;这样我的排序函数就知道要按哪个属性排序。

For example if my array is

例如,如果我的数组是

[
  {
    "name": "John",
    "age": "16"
  },
  {
    "name": "Charles",
    "age": "26"
  }
]

I want to avoid writing different if cases to know if I should sort by name or age. I just want to pass a parameter 'name' or 'age' and my sorting function should know what to do.

我想避免写不同的 if 案例来知道我是否应该按姓名或年龄排序。我只想传递一个参数“名称”或“年龄”,我的排序功能应该知道该怎么做。

Thanks.

谢谢。

回答by Engineer

Something like a:

类似的东西:

function predicateBy(prop){
   return function(a,b){
      if (a[prop] > b[prop]){
          return 1;
      } else if(a[prop] < b[prop]){
          return -1;
      }
      return 0;
   }
}

//Usage
yourArray.sort( predicateBy("age") );
yourArray.sort( predicateBy("name") );

回答by agershun

You can sort arrays by any field with Alasqllibrary:

您可以使用Alasql库按任何字段对数组进行排序:

var data = [{"name":"John", "age":"16"}, {"name":"Charles", "age":"26"}];

var res1 = alasql('SELECT * FROM ? ORDER BY name',[data]);
var res2 = alasql('SELECT * FROM ? ORDER BY age',[data]);
var res3 = alasql('SELECT * FROM ? ORDER BY age, name',[data]);
var res4 = alasql('SELECT * FROM ? ORDER BY age DESC, name ASC',[data]);

Try this example in jsFiddle.

在 jsFiddle 中试试这个例子。

回答by Anand

See this example http://jsfiddle.net/W8Byu/1/

请参阅此示例 http://jsfiddle.net/W8Byu/1/

What I have done is stored the sort column Name in a variable and used in Sort function.

我所做的是将排序列 Name 存储在一个变量中并在 Sort 函数中使用。

 var sortColumnName = "Name";

 function SortByName(x,y) {
      return ((x[sortColumnName]  == y[sortColumnName]) ? 0 : ((x[sortColumnName]>    y[sortColumnName]) ? 1 : -1 ));
    }