在 Python 3.3 中格式化时间字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21618351/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Format time string in Python 3.3
提问by markmnl
I am trying to get current local time as a string in the format: year-month-day hour:mins:seconds. Which I will use for logging. By my reading of the documentation I can do this by:
我试图以以下格式将当前本地时间作为字符串获取：年-月-日小时：分钟：秒。我将用于日志记录。通过阅读文档，我可以通过以下方式做到这一点：
import time
'{0:%Y-%m-%d %H:%M:%S}'.format(time.localtime())
However I get the error:
但是我收到错误：
Traceback (most recent call last): File "", line 1, in ValueError: Invalid format specifier
What am I doing wrong? Is there a better way?
我究竟做错了什么？有没有更好的办法？
采纳答案by falsetru
time.localtimereturns time.struct_timewhich does not support strftime-like formatting.
time.localtime返回time.struct_time不支持类似 strftime 的格式。
Pass datetime.datetimeobject which support strftime formatting. (See datetime.datetime.__format__)
传递datetime.datetime支持 strftime 格式的对象。（见datetime.datetime.__format__）
>>> import datetime
>>> '{0:%Y-%m-%d %H:%M:%S}'.format(datetime.datetime.now())
'2014-02-07 11:52:21'
回答by sashkello
回答by seaders
And for newer versions of Python (3.6+, https://www.python.org/dev/peps/pep-0498/purely for completeness), you can use the newer string formatting, ie.
对于较新版本的 Python（3.6+，https://www.python.org/dev/peps/pep-0498/纯粹是为了完整性），您可以使用较新的字符串格式，即。
import datetime
today = datetime.date.today()
f'{today:%Y-%m-%d}'
> '2018-11-01'
