Bash - 如何使用 printf 打印多行字符串（带有 '\n'）
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Bash - How to print multi line strings (with '\n') using printf
提问by wolfgang
i'm trying to print a multi line strings in printfthis way
我正在尝试以printf这种方式打印多行字符串
printf "hi\n"
printf "next line here\n"
I can't do the following
我不能执行以下操作
text_content="
hi
next line here
"
printf $text_content
Is there any other way?
有没有其他办法？
回答by Reuben L.
Quoting the variable should do the trick. In your example, however, you are getting double newlines.
引用变量应该可以解决问题。但是，在您的示例中，您将获得双换行符。
printf "$text_content"
回答by Andrew
If printf is not necessary, then you may use echo:
如果不需要 printf，则可以使用 echo：
var="one\ntwo"
echo -e $var
回答by tripleee
Here's another variation.
这是另一种变体。
printf '%s\n' 'first line here' 'second line here'
You can add an arbitrary number of arguments; printfwill repeat the format string until all arguments are exhausted.
您可以添加任意数量的参数；printf将重复格式字符串，直到用完所有参数。
printf '%s\n' '#!/bin/sh' \
'for x; do' \
' echo "Welcome to my script!"' \
'done' >script.sh
