使用 Java 的 XPath 循环节点并提取特定的子节点值

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时间:2020-10-30 04:18:00  来源:igfitidea点击:

Looping over nodes and extracting specific subnode values using Java's XPath

javaxpath

提问by BoomShaka

I understand from Googling that it makes more sense to extract data from XML using XPath than by using DOM looping.

我从谷歌搜索中了解到,使用 XPath 从 XML 中提取数据比使用 DOM 循环更有意义。

At the moment, I have implemented a solution using DOM, but the code is verbose, and it feels untidy and unmaintainable, so I would like to switch to a cleaner XPath solution.

目前我已经实现了一个使用DOM的解决方案,但是代码比较冗长,感觉不整洁,难以维护,所以想换一个更简洁的XPath方案。

Let's say I have this structure:

假设我有这个结构:

<products>
    <product>
        <title>Some title 1</title>
        <image>Some image 1</image>
    </product>
    <product>
        <title>Some title 2</title>
        <image>Some image 2</image>
    </product>
    ...
</products>

I want to be able to run a for loop for each of the <product>elements, and inside this for loop, extract the title and image node values.

我希望能够为每个<product>元素运行一个 for 循环,并在这个 for 循环中提取标题和图像节点值。

My code looks like this:

我的代码如下所示:

InputStream is = conn.getInputStream();          
DocumentBuilder builder =
  DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = builder.parse(is);
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("/products/product");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList products = (NodeList) result;
for (int i = 0; i < products.getLength(); i++) {
    Node n = products.item(i);
    if (n != null && n.getNodeType() == Node.ELEMENT_NODE) {
        Element product = (Element) n;
        // do some DOM navigation to get the title and image
    }
}

Inside my forloop I get each <product>as a Node, which is cast to an Element.

在我的for循环中,我将每个都<product>作为 a Node,将其强制转换为Element.

Can I simply use my instance of XPathExpressionto compile and run another XPathon the Nodeor the Element?

我可以简单地使用我的实例在或上XPathExpression编译和运行另一个吗?XPathNodeElement

回答by Gopi

Yes, you can always do like this -

是的,你总是可以这样做——

XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("/products/product");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
expr = xpath.compile("title"); // The new xpath expression to find 'title' within 'product'.

NodeList products = (NodeList) result;
for (int i = 0; i < products.getLength(); i++) {
    Node n = products.item(i);
    if (n != null && n.getNodeType() == Node.ELEMENT_NODE) {
        Element product = (Element) n;
        NodeList nodes = (NodeList)  expr.evaluate(product,XPathConstants.NODESET); //Find the 'title' in the 'product'
        System.out.println("TITLE: " + nodes.item(0).getTextContent()); // And here is the title 
    }
}    

Here I have given example of extracting the 'title' value. In same way you can do for 'image'

在这里,我给出了提取“标题”值的示例。以同样的方式你可以为“图像”做

回答by dogbane

I'm not a big fan of this approach because you have to build a document (which might be expensive) before you can apply XPaths to it.

我不是这种方法的忠实粉丝,因为您必须先构建一个文档(这可能很昂贵),然后才能对其应用 XPath。

I've found VTD-XMLa lot more efficient when it comes to applying XPaths to documents, because you don't need to load the whole document into memory. Here is some sample code:

我发现VTD-XML在将 XPath 应用于文档时效率更高,因为您不需要将整个文档加载到内存中。下面是一些示例代码:

final VTDGen vg = new VTDGen();
vg.parseFile("file.xml", false);
final VTDNav vn = vg.getNav();
final AutoPilot ap = new AutoPilot(vn);

ap.selectXPath("/products/product");
while (ap.evalXPath() != -1) {
    System.out.println("PRODUCT:");

    // you could either apply another xpath or simply get the first child
    if (vn.toElement(VTDNav.FIRST_CHILD, "title")) {
        int val = vn.getText();
        if (val != -1) {
            System.out.println("Title: " + vn.toNormalizedString(val));
        }
        vn.toElement(VTDNav.PARENT);
    }
    if (vn.toElement(VTDNav.FIRST_CHILD, "image")) {
        int val = vn.getText();
        if (val != -1) {
            System.out.println("Image: " + vn.toNormalizedString(val));
        }
        vn.toElement(VTDNav.PARENT);
    }
}

Also see this post on Faster XPaths with VTD-XML.

另请参阅有关使用 VTD-XML 的 Faster XPaths 的这篇文章。