php 用于检查网站 url 的正则表达式
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Regular expression for checking website url
提问by Linto davis
I need to check the web address, using regular expression.
我需要使用正则表达式检查网址。
if user type url as
如果用户键入 url 作为
- www.test.com
- http://www.test.com
- https://www.test.com
- www.test.com
- http://www.test.com
- https://www.test.com
i have a regular expression like
我有一个正则表达式，比如
/^(http\:\/\/[a-zA-Z0-9_\-]+(?:\.[a-zA-Z0-9_\-]+)*\.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+\.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/
but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too
但它只允许第二个选项。我如何修改正则表达式，以便它也应该接受第一个和第三个选项
回答by Salman A
This is a pretty basic expression for testing domain names:
这是用于测试域名的非常基本的表达式：
@^(http\:\/\/|https\:\/\/)?([a-z0-9][a-z0-9\-]*\.)+[a-z0-9][a-z0-9\-]*$@i
Should match:
应该匹配：
domain.com
www.domain.com
http://domain.com
https://domain.com
回答by rekha_sri
Use the following program for validating the website URL.
使用以下程序验证网站 URL。
It will be validating the following and any valid website URL.
它将验证以下和任何有效的网站 URL。
- www.test.com
- http://www.test.com
- https://www.test.com
- www.test.com
- http://www.test.com
- https://www.test.com
<?php
$string_url="https://www.test.com";
$reg_exp = "/^(http(s?):\/\/)?(www\.)+[a-zA-Z0-9\.\-\_]+(\.[a-zA-Z]{2,3})+(\/[a-zA-Z0-9\_\-\s\.\/\?\%\#\&\=]*)?$/";
if(preg_match($reg_exp, $string_url) == TRUE){
echo "URL is valid format";
}
else{
echo "URL is invalid format";
}
?>
回答by codaddict
You can make the http://optional and also the sin httpsoptional as:
您可以在http://可选的，也是s在https可选为：
/^((?:http(?:s)?\:\/\/)?[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/
回答by Mohd Haider
You can use this pattern also:
您也可以使用此模式：
(http(s)?://)?([\w-]+\.)+[\w-]+(/[\w- ;,./?%&=]*)?
This will work for matching:
这将适用于匹配：
http://www.google.com
https://www.google.com
www.google.com
google.com
google.in
Simple pattern for matching.
简单的匹配模式。
Hope this will help someone!!!
希望这会帮助某人！！！
回答by Swadesh Ranjan Dash
Pattern
图案
(https?:\/\/)?([\w\d]+\.)?[\w\d]+\.\w+\/?.+
(https?:\/\/)?([\w\d]+\.)?[\w\d]+\.\w+\/?.+
This will work for matching:
这将适用于匹配：
www.demo.com
www.demo.com
回答by 1ce
Try the following instead :
请尝试以下操作：
filter_var($your_variable, FILTER_VALIDATE_URL);
