java Java从最小到最大对数组进行排序的方法
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Method to sort an array from least to greatest Java
提问by Panthy
Hi I am trying to create a method that finds the mode of an array. To do this I first need to create a method that sorts the list from least to greatest but I am not sure what I am doing wrong in the first place
嗨，我正在尝试创建一种查找数组模式的方法。为此，我首先需要创建一个方法，将列表从最小到最大排序，但我不确定我首先做错了什么
public class Mode {
public int [] sort(int[] asd) {
int[] sorted = new int[10];
for (int i = 0; i < asd.length; i++) {
for (int j = 1; j < asd.length; j++) {
if ( (asd[i] > asd[j]) && (i != j) ) {
int temp = asd[j];
asd[j] = asd[i];
asd[i] = asd[temp];
}
else
continue;
}
}
return sorted;
}
public static void main(String[] args) {
Mode list1 = new Mode();
int[] array = {3,2,5,4,1,1,1,1,10,9};
int[] potato = list1.sort(array);
for (int i = 0; i < potato.length; i++)
System.out.print(potato[i]);
}
}
When I run this, I get 0000000000 as an output. I think there is something wrong in the method since I am returning an array that has been initialized but nothing has been put in there. How do I (in my nested for loop) add each number in the sorted array?
当我运行它时，我得到 0000000000 作为输出。我认为该方法有问题，因为我返回了一个已初始化但未放入任何内容的数组。我如何（在我的嵌套 for 循环中）添加排序数组中的每个数字？
回答by vikingsteve
There were some issues in your code, they are fixed as per below:
您的代码中存在一些问题，它们已按以下方式修复：
public class Mode {
public int [] sort(int[] asd) {
int[] sorted = asd.clone();
for (int i = 0; i < sorted.length; i++) {
for (int j = i+1; j < sorted.length; j++) {
if ( (sorted[i] > sorted[j]) && (i != j) ) {
int temp = sorted[j];
sorted[j] = sorted[i];
sorted[i] = temp;
}
}
}
return sorted;
}
public int findMode(int[] sorted) {
// do whatever you want to do here...
return 0;
}
public static void main(String[] args) {
Mode list1 = new Mode();
int[] array = {3,2,5,4,1,1,1,1,10,9};
int[] potato = list1.sort(array);
for (int i = 0; i < potato.length; i++) {
System.out.print(potato[i] + ",");
}
System.out.println();
System.out.print(list1.findMode(potato));
}
}
To explain, previously you were sorting asd. Now we are sorting sorted, which starts as a copy of asd.
解释一下，之前您正在对asd. 现在我们正在排序sorted，它从asd.
The loop for jshould start at i+1.
for 循环j应该从 开始i+1。
The last part of your "swap" operation should be sorted[i] = temp.
“交换”操作的最后一部分应该是sorted[i] = temp.
回答by Prasad Khode
You can use java.util.Arraysto sort the array in ascending order
您可以使用java.util.Arrays按升序对数组进行排序
public class SortArray {
public static void main(String[] args) {
int[] array = { 3, 2, 5, 4, 1, 1, 1, 1, 10, 9 };
Arrays.sort(array);
for (int i = 0; i < array.length; i++) {
System.out.print(array[i] + " ");
}
}
}
The output for the above code snippet will be
上述代码片段的输出将是
1 1 1 1 2 3 4 5 9 10
回答by Bruce Collie
You are assigning to elements of asdin your sort method, then returning the array sorted, which is never altered in your sortmethod.
您asd在 sort 方法中分配给元素，然后返回 array sorted，它在您的sort方法中永远不会改变。
Additionally, you should initialise your sortedarray to be the same size as asd.
此外，您应该将sorted数组初始化为与asd.
