java 递归 XML 解析器

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时间:2020-10-31 12:10:56  来源:igfitidea点击:

Recursive XML-parser

javaxmlrecursionxml-parsing

提问by zingo

I have the following xml file:

我有以下 xml 文件:

<?xml version="1.0"?>
<CONFIG>
    <FUNCTION>
        <NAME>FUNCT0</NAME>
        <CALLS>
            <FUNCTION>
            <NAME>FUNCT0_0</NAME>
            </FUNCTION>
        </CALLS>
        <CALLS>
            <FUNCTION>
            <NAME>FUNCT0_1</NAME>
            </FUNCTION>
        </CALLS>
    </FUNCTION>
    <FUNCTION>
        <NAME>FUNCT1</NAME>
    </FUNCTION>
</CONFIG>

I have a class called FunctionInfo which stores both a function's name and also contains an ArrayList to contains the subfunctions which the function calls.

我有一个名为 FunctionInfo 的类,它既存储函数的名称,又包含一个 ArrayList 以包含函数调用的子函数。

I want to end up with an ArrayList which contains the top-level functions that will then store their subfunctions inside the object recursively.

我想最终得到一个 ArrayList,它包含顶级函数,然后将它们的子函数递归地存储在对象中。

I need this to work for an indefinite depth of recursion.

我需要它来为无限的递归深度工作。

My question is what is the easiest way to write a recursive XML parser that can perform this task?

我的问题是编写可以执行此任务的递归 XML 解析器的最简单方法是什么?

Edit: I am working in Java.

编辑:我在 Java 工作。

Thanks :)

谢谢 :)

回答by thedayofcondor

Unless your file is huge, you can use the java DOM parser (the DOM parser keeps the file in memory)

除非您的文件很大,否则您可以使用 java DOM 解析器(DOM 解析器将文件保存在内存中)

Given a node (starting with the root), you can enumerate its children, and then call the same function on each child recursively.

给定一个节点(从根开始),您可以枚举其子节点,然后对每个子节点递归调用相同的函数。

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class RecursiveDOM {
    public static void main(final String[] args) throws SAXException, IOException, ParserConfigurationException {
        new RecursiveDOM("file.xml");
    }

    public RecursiveDOM(final String file) throws SAXException, IOException, ParserConfigurationException {
        final DocumentBuilderFactory dbfac = DocumentBuilderFactory.newInstance();
        final DocumentBuilder docBuilder = dbfac.newDocumentBuilder();
        final Document doc = docBuilder.parse(this.getClass().getResourceAsStream(file));
        final List<String> l = new ArrayList<String>();
        parse(doc, l, doc.getDocumentElement());
        System.out.println(l);
    }

    private void parse(final Document doc, final List<String> list, final Element e) {
        final NodeList children = e.getChildNodes();
        for (int i = 0; i < children.getLength(); i++) {
            final Node n = children.item(i);
            if (n.getNodeType() == Node.ELEMENT_NODE) {
                list.add(n.getNodeName());
                parse(doc, list, (Element) n);
            }
        }
    }

}

Result:

结果:

[FUNCTION, NAME, CALLS, FUNCTION, NAME, CALLS, FUNCTION, NAME, FUNCTION, NAME]

回答by thedayofcondor

Also, you can consider using JAXB (mapping classes to XML), which would result in a tree of java classes, if implemented properly each class can implement a particular type of function so the tree can be recursively "calculated".

此外,您可以考虑使用 JAXB(将类映射到 XML),这将产生 Java 类树,如果正确实现,每个类都可以实现特定类型的函数,因此可以递归地“计算”树。

This is a basic JAXB implementation, use Config.unmarshal to rebuild it from an InputStream:

这是一个基本的 JAXB 实现,使用 Config.unmarshal 从 InputStream 重建它:

import java.io.OutputStream;
import java.io.Reader;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

public class TestJAXB {

    public static void main(final String[] args) throws JAXBException {
        final Function e5 = new Function("N5", null);
        final Function e6 = new Function("N6", null);
        final Function e4 = new Function("N4", null);
        final Function e2 = new Function("N2", ((new Call[] { new Call(e4) })));
        final Function e3 = new Function("N3", ((new Call[] { new Call(e5) })));
        final Function e1 = new Function("N1", ((new Call[] { new Call(e2), new Call(e3) })));
        new Config(new Function[] { e1, e6 }).marshall(System.out);
    }

    @XmlRootElement(name = "CONFIG")
    static class Config {
        @XmlElement(name = "FUNCTION")
        private Function[] functions;

        public Config(final Function[] f) {
            this.functions = f;
        }

        protected Config() {
        }

        public void marshall(final OutputStream out) throws JAXBException {
            final JAXBContext jaxbContext = JAXBContext.newInstance(this.getClass());
            final Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
            marshaller.marshal(this, out);
        }

        public final static Config unmarshall(final Reader r) throws JAXBException {
            final JAXBContext jaxbContext = JAXBContext.newInstance(Config.class);
            final Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            return (Config) unmarshaller.unmarshal(r);
        }

    }

    @XmlRootElement(name = "FUNCTION")
    static class Function {
        @XmlElement(name = "NAME")
        String name;

        @XmlElement(name = "CALLS")
        Call[] calls;

        public Function(final String name, final Call[] calls) {
            this.name = name;
            this.calls = calls;
        }

        protected Function() {
        }

    }

    @XmlRootElement(name = "CALL")
    static class Call {
        @XmlElement(name = "FUNCTION")
        Function f;

        protected Call() {
        }

        public Call(final Function f) {
            this.f = f;
        }

    }
}