Java / Groovy 中的 Base64 编码
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Base64 encoding in Java / Groovy
提问by Josh K
What is the proper way to convert a byte [] to a Base64 string in Java? Better yet would be Grails / Groovy because it tells me that the encodeAsBase64()function is deprecated. The sun.misc.BASE64Encoderpackage isn't recommended for use and outputs a different size string on some Windows platforms.
在 Java 中将字节 [] 转换为 Base64 字符串的正确方法是什么？更好的是 Grails/Groovy，因为它告诉我该encodeAsBase64()函数已被弃用。sun.misc.BASE64Encoder不推荐使用该包并在某些 Windows 平台上输出不同大小的字符串。
采纳答案by Evan Mulawski
Apache Commons has many utilities:
Apache Commons 有许多实用程序：
Binary Package: http://commons.apache.org/codec/apidocs/org/apache/commons/codec/binary/Base64.html
二进制包：http: //commons.apache.org/codec/apidocs/org/apache/commons/codec/binary/Base64.html
Download: http://commons.apache.org/codec/download_codec.cgi
回答by Mark O'Connor
You could use the open source Base64Coderlibrary
您可以使用开源Base64Coder库
import biz.source_code.base64Coder.Base64Coder
@Grab(group='biz.source_code', module='base64coder', version='2010-09-21')
String s1 = Base64Coder.encodeString("Hello world")
String s2 = Base64Coder.decodeString("SGVsbG8gd29ybGQ=")
回答by ataylor
The preferred way to do this in groovy is:
在 groovy 中执行此操作的首选方法是：
def encoded = "Hello World".bytes.encodeBase64().toString()
assert encoded == "SGVsbG8gV29ybGQ="
def decoded = new String("SGVsbG8gV29ybGQ=".decodeBase64())
assert decoded == "Hello World"
回答by srsajid
Implement your own method like this :)
像这样实现你自己的方法:)
public class Coder {
private static final String base64code = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
public static String encodeAsBase64(String toEncode) {
return encodeAsBase64(toEncode.getBytes())
}
public static String encodeAsBase64(byte[] toEncode) {
int pos = 0;
int onhand = 0;
StringBuffer buffer = new StringBuffer();
for(byte b in toEncode) {
int read = b;
int m;
if(pos == 0) {
m = (read >> 2) & 63;
onhand = read & 3;
pos = 1;
} else if(pos == 1) {
m = (onhand << 4) + ((read >> 4) & 15);
onhand = read & 15;
pos = 2;
} else if(pos == 2) {
m = ((read >> 6) & 3) + (onhand << 2);
onhand = read & 63;
buffer.append(base64code.charAt(m));
m = onhand;
onhand = 0;
pos = 0;
}
buffer.append(base64code.charAt(m));
}
while(pos > 0 && pos < 4) {
pos++;
if(onhand == -1) {
buffer.append('=');
} else {
int m = pos == 2 ? onhand << 4 : (pos == 3 ? onhand << 2 : onhand);
onhand = -1;
buffer.append(base64code.charAt(m));
}
}
return buffer.toString()
}
}
}
回答by Stefan Becker
(adding this to this thread in the hopes that somebody else will get a hit on this and doesn't have to waste his valuable time)
（将此添加到此线程中，希望其他人对此有所了解，而不必浪费他的宝贵时间）
I got stymied today when I tried to add in my Grails 2.3.11/Groovy 2.1.9 application the output of
今天，当我尝试在 Grails 2.3.11/Groovy 2.1.9 应用程序中添加
String src = render(
model: ...,
template: ...,
)
.encodeAsBase64()
as a data-attribute to a DOM element. But the atob()in the corresponding JavaScript, i.e. the code that decodes the Base64 string from the data attribute, kept complaining about illegal characters, while other decoders, e.g. base64 -daccepted the same Base64 string without problems.
作为data-DOM 元素的属性。但是atob()在相应的 JavaScript 中，即从 data 属性解码 Base64 字符串的代码，不断抱怨非法字符，而其他解码器，例如，base64 -d接受相同的 Base64 字符串没有问题。
The solution is to force the render()return value to a single string and then apply the Base64 encoding, i.e.
解决办法是强制render()返回值为单个字符串，然后应用Base64编码，即
String src = render(
model: ...,
template: ...,
)
.toString()
.encodeAsBase64()
or (if you consider encodeAsBase64()as deprecated):
或（如果您认为encodeAsBase64()已弃用）：
String src = render(
model: ...,
template: ...,
)
.toString()
.bytes
.encodeBase64() // add 'true' for chunked output
