php 获取当前年份的最后一天作为日期
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Get the last day of the current year as date
提问by user2571510
How can I get the last day (Dec 31) of the current year as a date using PHP?
如何使用 PHP 获取当前年份的最后一天（12 月 31 日）作为日期？
I tried the following but this doesn't work:
我尝试了以下操作，但这不起作用：
$year = date('Y');
$yearEnd = strtotime($year . '-12-31');
What I need is a date that looks like 2014-12-31 for the current year.
我需要的是今年看起来像 2014-12-31 的日期。
回答by AbraCadaver
PHP strtotime()uses the current date/time as a basis (so it will use this current year), and you need date()to format:
PHPstrtotime()使用当前日期/时间作为基础（因此它将使用当前年份），并且您需要date()格式化：
$yearEnd = date('Y-m-d', strtotime('Dec 31'));
//or
$yearEnd = date('Y-m-d', strtotime('12/31'));
回答by Fabio
You can just concatenate actual year with required date
您可以将实际年份与所需日期连接起来
$year = date('Y') . '-12-31';
echo $year;
//output 2014-12-31
回答by xtra
DateTime is perfectly capable of doing this:
DateTime 完全有能力做到这一点：
$endOfYear = new \DateTime('last day of December this year');
You can even combine it with more modifiers to get the end of next year:
您甚至可以将其与更多修改器结合使用，以获得明年年底：
$endOfNextYear = new \DateTime('last day of December this year +1 years');
回答by Maurice
Another way to do this is use the Relative Formats of strtotime()
另一种方法是使用相对格式 strtotime()
$yearEnd = date('Y-m-d', strtotime('last day of december this year'));
// or
$yearEnd = date('Y-m-d', strtotime('last day of december'));
