Android 错误获取资源编号值时没有包标识符
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ERROR No package identifier when getting value for resource number
提问by Dean-O
Both activities are in the same package
两个活动在同一个包中
Second activity uses second layout file
第二个活动使用第二个布局文件
setContentView(R.layout.main2);
Errors on this line in the Second_Activity.
Second_Activity 中这一行的错误。
EditText text1 = (EditText) findViewById(R.id.EditText03);
Here is the layout file for the Second_Activity.
这是 Second_Activity 的布局文件。
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<LinearLayout
android:id="@+id/LinearLayout01"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
<TextView
android:id="@+id/TextView01"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Answer Is : " >
</TextView>
<EditText
android:id="@+id/EditText03"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
</EditText>
</LinearLayout>
<Button
android:id="@+id/Button01"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="onClick"
android:text="Calling an intent" >
</Button>
</LinearLayout>
Here are the errors in the LogCat window
以下是 LogCat 窗口中的错误
08-01 19:32:20.340: WARN/ResourceType(8875): No package identifier when getting value for resource number 0x00000005
08-01 19:32:20.390: ERROR/AndroidRuntime(8875): Caused by: android.content.res.Resources$NotFoundException: String resource ID #0x5
mail.xml
邮件.xml
<TextView
android:id="@+id/TextView01"
android:layout_width="wrap_content"
android:layout_height="wrap_content" android:text="First Number : ">
</TextView>
<EditText
android:id="@+id/EditText01"
android:inputType="number"
android:layout_width="wrap_content"
android:layout_height="wrap_content">
</EditText>
<TextView
android:id="@+id/TextView02"
android:layout_width="wrap_content"
android:layout_height="wrap_content" android:text="Second Number: ">
</TextView>
<EditText
android:id="@+id/EditText02"
android:inputType="number"
android:layout_width="wrap_content"
android:layout_height="wrap_content">
</EditText>
secondscreen.xml
第二屏.xml
<TextView
android:id="@+id/TextView03"
android:layout_width="wrap_content"
android:layout_height="wrap_content" android:text="Answer Is : ">
</TextView>
<EditText
android:id="@+id/main2EditText01"
android:inputType="number"
android:layout_width="wrap_content"
android:layout_height="wrap_content">
</EditText>
manifest xml file
清单 xml 文件
<activity android:name=".ActivityTwo"/>
回答by John Weidner
I got this same error message when I tried to use TextView.setText passing a char instead of a String. This makes sense since the char would be promoted to an int which meant that I was really calling the
当我尝试使用 TextView.setText 传递一个字符而不是一个字符串时，我收到了同样的错误消息。这是有道理的，因为 char 将被提升为 int，这意味着我真的在调用
TextView.setText( int resId );
And since there wasn't a resource with that value, it wouldn't work.
并且由于没有具有该值的资源，因此它不起作用。
回答by u1201201
face with the same error
面对同样的错误
finally i found its not a error due to your xml layout
最后我发现它不是由于您的 xml 布局导致的错误
somewhere in your code set TextView.setText(int)
在你的代码集中的某个地方 TextView.setText(int)
try TextView.setText( Integer.toString(int));
尝试 TextView.setText( Integer.toString(int));
回答by Henok
When you pass an integer to the TextView.setText()to be displayed android assumes it is a resource id and that's why you are getting Resource$NotFoundException. Try converting the int to String before passing it to TextView.setText(): TextView.setText(String.valueOf(i)).
当您将一个整数传递TextView.setText()给要显示的 android 时，它会假定它是一个资源 ID，这就是您获得Resource$NotFoundException. 在将 int 传递给TextView.setText():之前尝试将其转换为 String TextView.setText(String.valueOf(i))。
回答by Paul
Just for the protocol, You could also use:
仅用于协议，您还可以使用：
TextView.setText("" + intVar)instead of TextView.setText(intVar)
TextView.setText("" + intVar)代替 TextView.setText(intVar)
回答by Vignan Nani
I got the same error while trying to print integer value : TextView.setText(int value). I resolved this error by converting the integer value to string and the i used TextView.setText(converted string value)
我在尝试打印整数值时遇到了同样的错误：TextView.setText(int value)。我通过将整数值转换为字符串解决了这个错误，我使用了 TextView.setText(converted string value)
回答by nekiala
I had the same problem before I come to this post.
For me, it was like this: view_element.setText( an_int_value).
After casting view_element.setText(String.valueOf(an_int_value));, everything is okay.
在我来这篇文章之前，我遇到了同样的问题。对我来说，它是这样的：view_element.setText( an_int_value). 铸造后view_element.setText(String.valueOf(an_int_value));，一切正常。
回答by Rigoberto Torres
From Android TextView Documentation:
setText(int resid)Sets the text to be displayed using a string resource identifier.
setText(int resid)使用字符串资源标识符设置要显示的文本。
回答by Lucy Lu
For me I had to go in the XML file for the button. There I noticed a hard coded string value. I had to remove that, and also I had to use Textview.setText("" + intVar);
对我来说，我必须进入按钮的 XML 文件。在那里我注意到一个硬编码的字符串值。我不得不删除它，而且我不得不使用Textview.setText("" + intVar);
回答by Ankit Gupta
It is due to typecast error. You have to try this- TextView.setText(Integer.toString(variable_name));
这是由于类型转换错误。你必须试试这个- TextView.setText(Integer.toString(variable_name));
Here toString is used to convert integer to string for showing text.
这里 toString 用于将整数转换为字符串以显示文本。
回答by saintjab
I was using Picasso library to load image from the network. The urls are in a ArrayList I wasn't using arraylist.get() to get the position of the url in the ArrayList.
我正在使用毕加索库从网络加载图像。网址在 ArrayList 中，我没有使用 arraylist.get() 来获取网址在 ArrayList 中的位置。
