Python ValueError:传递值的形状是 (1, 6),索引意味着 (6, 6)

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时间:2020-08-19 19:24:51  来源:igfitidea点击:

ValueError: Shape of passed values is (1, 6), indices imply (6, 6)

pythonpandasflaskvalueerror

提问by Sbk3824

I am passing a list from flask function to another function, and getting this value error.

我正在将一个列表从 Flask 函数传递给另一个函数,并得到这个值错误。

My code at sending end:

我在发送端的代码:

@app.route('/process', methods=['POST'])
def process():
    name = request.form['name']
    comment = request.form['comment']
    wickets = request.form['wickets']
    ga = request.form['ga']
    ppballs = request.form['ppballs']
    overs = request.form['overs']

    score = [name,comment,wickets,ga,ppballs,overs]
    results = []
    results = eval_score(score)
    print results

Receiver end :

接收端:

def ml_model(data):
    col = pd.DataFrame(data,columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
    predicted = predictor(col)

Trace of Error:

错误跟踪:

 ...
 line 1598, in dispatch_request
 return self.view_functions[rule.endpoint](**req.view_args)

 File "/Users/sbk/guestbook/guestbook.py", line 26, in process
 results = eval_score(score)

 File "/Users/sbk/guestbook/eval_score.py", line 6, in eval_score
 col = pd.DataFrame(data,columns=['runs','balls', 'wickets',  'ground_average', 'pp_balls_left', 'total_overs'])

 File "/Users/sbk/anaconda2/lib/python2.7/site-  packages/pandas/core/frame.py", line 385, in __init__
 copy=copy)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/frame.py", line 533, in _init_ndarray
 return create_block_manager_from_blocks([values], [columns, index])

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4631, in  create_block_manager_from_blocks
 construction_error(tot_items, blocks[0].shape[1:], axes, e)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4608, in construction_error
 Open an interactive python shell in this framepassed, implied))

Please let me know where I am going wrong.

请让我知道我哪里出错了。

回答by rafaelc

Simply change

简单地改变

col = pd.DataFrame(data, columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

for

为了

col = pd.DataFrame([data], columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

You want [data]for pandasto understand they're rows.

你想[data]pandas了解他们的行。



Simple illustration:

简单说明:

a = [1, 2, 3]
>>> pd.DataFrame(a)
   0
0  1
1  2
2  3

>>> pd.DataFrame([a])
   0  1  2
0  1  2  3

回答by Candice Withrow

I was having similar issues with making a dataframe from regressor coefficients (regressor.coeff_), and brackets gave another error asking for 2-d input. If you get this error, try appending the input array with [0] so it pulls the values out. ex: data[0]

我在从回归系数(regressor.coeff_)制作数据帧时遇到了类似的问题,括号给出了另一个要求二维输入的错误。如果您收到此错误,请尝试使用 [0] 附加输入数组,以便将值拉出。例如:数据[0]