Java 在字符串中放置一个空格
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Putting a space in a string
提问by Emmanuel
Assuming I have a String like "MikeHymanson" I am trying to figure out a way to put a space in between so it becomes "Mike Hymanson". And then applying the same method to another string say "JohnBull" would give me back "John Bull". This is the code I came up with:
假设我有一个像“MikeHymanson”这样的字符串，我正试图找出一种在两者之间放置一个空格的方法，这样它就变成了“Mike Hymanson”。然后对另一个字符串应用相同的方法说“JohnBull”会给我回“John Bull”。这是我想出的代码：
public class Test{
public Test(){
}
public void sep(String s){
s = s + " ";
char[] charArray = s.toCharArray();
int l = s.length();
for (int i = 0; i < l; i++){
char p = ' ';
if(Character.isUpperCase(s.charAt(0))){
continue;
}
else if (Character.isUpperCase(s.charAt(i))){
int k = s.indexOf(s.charAt(i));
charArray[l] = charArray[--l];
charArray[k-1] = p;
}
//System.out.println(s.charAt(i));
}
}
public static void main (String args[]){
Test one = new Test();
one.sep("MikeHymanson");
}
}
My idea was to add a space to the String so that "MikeHymanson" becomes "Mike Hymanson " and then shift the characters on place to the right (check for where I find an uppercase) ignoring the first uppercase. Then put a character ' ' in place of the character 'J' but shift 'J' to the right. That's what I was trying to achieve with my method but it looks I need some guidelines. If anyone could help. Thanks.
我的想法是在字符串中添加一个空格，以便“MikeHymanson”变成“Mike Hymanson”，然后将字符向右移动（检查我找到大写的位置）忽略第一个大写。然后将字符 ' ' 放在字符 'J' 的位置，但将 'J' 向右移动。这就是我试图用我的方法实现的目标，但看起来我需要一些指导方针。如果有人可以帮忙。谢谢。
采纳答案by Silviu Burcea
Try this:
尝试这个：
"MikeHymanson".replaceAll("(?!^)([A-Z])", " ");
For every upper char I am adding a space before.
对于每个上层字符，我之前都添加了一个空格。
Also, it works with multiple uppercase words.
I am getting Word1 Word2 Word3for Word1Word2Word3.
此外，它适用于多个大写单词。我得到Word1 Word2 Word3了Word1Word2Word3。
回答by RamonBoza
String is finaland immutable, you cannot modify it, you will always use it to create a new one and assign to any variable.
字符串是finaland immutable，您不能修改它，您将始终使用它来创建一个新的并分配给任何变量。
Being that said, i would recommend to look for the first non-zero index uppercase, get the substring where it is located, store the two substrings and add and space between.
话虽如此，我建议查找第一个非零索引大写字母，获取它所在的子字符串，存储两个子字符串并在它们之间添加和空格。
回答by X-Pippes
Similar question here: Insert Space After Capital letter
类似问题： 在大写字母后插入空格
try it and if you have any questions let us know!
试试吧，如果您有任何问题，请告诉我们！
the code from reference is here:
参考代码在这里：
String s = "HelloWorldNishant";
StringBuilder out = new StringBuilder(s);
Pattern p = Pattern.compile("[A-Z]");
Matcher m = p.matcher(s);
int extraFeed = 0;
while(m.find()){
if(m.start()!=0){
out = out.insert(m.start()+extraFeed, " ");
extraFeed++;
}
}
System.out.println(out);
回答by Jeroen Vannevel
public static void sep(String s) {
StringBuilder result = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
result.append(s.charAt(i));
if (i != s.length() -1 && Character.isUpperCase(s.charAt(i + 1))) {
result.append(" ");
}
}
System.out.println(result);
}
Simply add a space if the next character is uppercase.
如果下一个字符是大写，只需添加一个空格。
回答by npinti
The easiest way to go round this, in this case would be to use regular expressions
在这种情况下，最简单的方法是使用正则表达式
String str = "MikeHymanson";
System.out.println(str.replaceAll("(\w+?)([A-Z])(\w+?)", " "));
Yields: Mike Hymanson
产量： Mike Hymanson
回答by devnull
Using String.replaceAll:
String foo = "SomeLongName";
System.out.println(foo.replaceAll("([a-z]+)([A-Z])", " "));
Results in Some Long Name.
结果在Some Long Name.
回答by ferrerverck
public static String addSpaces(String str) {
StringBuilder sb = new StringBuilder();
if (str.length() == 0) return "";
sb.append(str.charAt(0));
for (int i = 1; i < str.length(); i++) {
if (Character.isUpperCase(str.charAt(i))) sb.append(" ");
sb.append(str.charAt(i));
}
return sb.toString();
}
