asp.net-mvc 如何创建 MVC 4 @Html.TextBox type="file"？
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How to create MVC 4 @Html.TextBox type="file"?
提问by Heidel
I need to add the following field at my form
我需要在我的表单中添加以下字段
<input type="file" class="input-file" />
I create model and describe this field (the last field)
我创建模型并描述这个字段（最后一个字段）
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
namespace CorePartners_Site2.Models
{
public class FeedbackForm
{
public string Name { get; set; }
public string Email { get; set; }
public string Phone { get; set; }
public string Company { get; set; }
public string AdditionalInformation { get; set; }
public HttpPostedFileBase ProjectInformation { get; set; }
}
}
and create
并创造
@Html.TextBox(null, null, new { type="file", @class="input-file" })
but it doesnt work, I get some exception. What's wrong?
但它不起作用，我有一些例外。怎么了？
回答by AliR?za Ad?yah?i
Model
模型
public class FeedbackForm
{
public string Name { get; set; }
public string Email { get; set; }
public string Phone { get; set; }
public string Company { get; set; }
public string AdditionalInformation { get; set; }
public HttpPostedFileBase ProjectInformation { get; set; }
}
View
看法
@model FeedbackForm
@Html.TextBox("Name")
@Html.TextBox("Email")
...
@Html.TextBox("ProjectInformation", null, new { type="file", @class="input-file" })
// submit button
My recommended view (strongly - typed)
我推荐的观点（强类型）
@model FeedbackForm
@Html.TextBoxFor(model=>model.Name)
@Html.TextBoxFor(model=>model.Email)
...
@Html.TextBoxFor(model=>model.ProjectInformation, null, new { type="file", @class="input-file" })
// submit button
Controller
控制器
[HttpPost]
public ActionResult FeedbackForm(FeedbackForm model)
{
// this is your uploaded file
var file = model.ProjectInformation;
...
return View();
}
MVC is using name convention, so if your textbox and model names match, then MVC will bind your inputs to your model.
MVC 使用命名约定，因此如果您的文本框和模型名称匹配，那么 MVC 会将您的输入绑定到您的模型。
回答by Julius Depulla
I think you are getting a null because you have not specified the enctype in your form tag.
我认为你得到了一个空值，因为你没有在你的表单标签中指定 enctype。
@using (Html.BeginForm("ActionMethodName", "Controller", FormMethod.Post, new { enctype = "multipart/form-data" })) { }
@using (Html.BeginForm("ActionMethodName", "Controller", FormMethod.Post, new { enctype = "multipart/form-data" })) { }
A working example always help.
一个有效的例子总是有帮助的。
回答by Tanmay
You can use the below syntax
您可以使用以下语法
@Html.TextBoxFor(model=>model.Email, new { @type="file", @class="input-file" })
回答by Henrique Brand?o
I solved this problem using enctype="multipart/form-data"
我解决了这个问题 enctype="multipart/form-data"
@using (Html.BeginForm("SalvarEvidencia", "Evidencia", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
...
}
回答by Erik Funkenbusch
There's nothing wrong with just using the input tag directly in your view. You aren't required to use a helper.
直接在视图中使用 input 标签并没有错。您不需要使用助手。
<input type="file" class="input-file" />
Just make sure it's within your BeginForm declaration block.
只需确保它在您的 BeginForm 声明块内。
回答by Kenneth
You need to specify the name of the field. If you don't want a name, nor a value, it's better to just include the field as is in your form.
您需要指定字段的名称。如果您不需要名称或值，最好只在表单中包含该字段。
It doesn't make sense to use a helper, if there's nothing dynamic about it.
如果没有任何动态，使用助手是没有意义的。
回答by user3452580
@using (Html.BeginForm("Action_Name", "Controller_Name",FormMethod.Post))
{
@Html.TextBoxFor(m => m.Email, new {@class = "text_field"})
@Html.ValidationMessageFor(m => m.Email)
}
