PHP - 致命错误:不支持的操作数类型

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时间:2020-08-25 05:03:11  来源:igfitidea点击:

PHP - Fatal error: Unsupported operand types

php

提问by tEcHnUt

I keep getting the following error and I was wondering on how to fix?

我不断收到以下错误,我想知道如何解决?

This is the second time I got this error I fixed it the first time but for some reason I cant fix it the second time.

这是我第二次遇到这个错误,我第一次修复了它,但由于某种原因我第二次无法修复它。

Fatal error: Unsupported operand types on line 103

Here is line 103.

这是第 103 行。

$avg = (round($total_rating_points / $total_ratings,1));

Here is the full code below.

这是下面的完整代码。

function getRatingText(){
    $dbc = mysqli_connect ("localhost", "root", "", "sitename");

    $page = '3';

    $sql1 = "SELECT COUNT(users_articles_id) 
             FROM articles_grades 
             WHERE users_articles_id = '$page'";

    $result = mysqli_query($dbc,$sql1);

    if (!mysqli_query($dbc, $sql1)) {
            print mysqli_error($dbc);
            return;
    }

    $total_ratings = mysqli_fetch_array($result);

    $sql2 = "SELECT grade_points 
             FROM grades 
             JOIN articles_grades ON grades.id = articles_grades.grade_id
             WHERE articles_grades.users_articles_id = '$page'";

    $result = mysqli_query($dbc, $sql2);

    if (!mysqli_query($dbc, $sql2)) {
            print mysqli_error($dbc);
            return;
    }

    while($row = mysqli_fetch_array($result)) {

        $trp[] = $row[0];
    }

    $total_rating_points = array_sum($trp);

    if (!empty($total_rating_points) && !empty($total_ratings)){
        $avg = (round($total_rating_points / $total_ratings,1));
        $votes = $total_ratings;
        echo $avg . "/10  (" . $votes . " votes cast)";
    } else {
        echo '(no votes cast)';
    }
}

回答by Pekka

$total_ratingsis an array, which you can't use for a division.

$total_ratings是一个数组,不能用于除法。

From above:

从上面:

$total_ratings = mysqli_fetch_array($result);

回答by SilentGhost

$total_ratingsis an array.

$total_ratings是一个数组。

回答by TeeHays

I had a similar error with the following code:-

我在以下代码中遇到了类似的错误:-

foreach($myvar as $key => $value){
    $query = "SELECT stuff
            FROM table
            WHERE col1 = '$criteria1'
            AND col2 = '$criteria2'";

    $result = mysql_query($query) or die('Could not execute query - '.mysql_error(). __FILE__. __LINE__. $query);               
    $point_values = mysql_fetch_assoc($result);
    $top_five_actions[$key] += $point_values; //<--- Problem Line       
}

It turned out that my $point_values variable was occasionally returning false which caused the problem so I fixed it by wrapping it in mysql_num_rows check:-

事实证明,我的 $point_values 变量偶尔会返回 false 这导致了问题,所以我通过将它包装在 mysql_num_rows 检查中来修复它:-

if(mysql_num_rows($result) > 0) {
        $point_values = mysql_fetch_assoc($result);
        $top_five_actions[$key] += $point_values;
}

Not sure if this helps though?

不确定这是否有帮助?

Cheers

干杯

回答by r3zn1k

I guess you want to do this:

我猜你想这样做:

$total_rating_count = count($total_rating_count);
if ($total_rating_count > 0) // because you can't divide through zero
   $avg = round($total_rating_points / $total_rating_count, 1);